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k + 4F; = 540 ... (2) Substitute 222 N for F and 50 cm for x in equation (1) 222 N = k (50 cm 222 N = k ( m) + F; Im)) + Fi 100 сm Rearrange above equation. k + 2F; = 444 .... (3) On solving above two equations (2) and (3), we get F; = 48 N and k = 348 N/m

k + 4F; = 540 ... (2) Substitute 222 N for F and 50 cm for x in equation (1) 222 N = k (50 cm 222 N = k ( m) + F; Im)) + Fi 100 сm Rearrange above equation. k + 2F; = 444 .... (3) On solving above two equations (2) and (3), we get F; = 48 N and k = 348 N/m

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I dont understand how they got from the equations (2) and (3) to fi=48 and k=348

Concept Used: The linear relation of spring force, the displacement and the preload is, F = kx + F; .. (1) Calculation: Substitute 135 N for F and 25 cm for x in equation (1) 135 N = k (25 cm 135 N = k (4 m) + F; Im 100 cm )) + F; Rearrange above equation. k+ 4F; = 540 . (2) Substitute 222 N for F and 50 cm for x in equation (1) 222 N = k (50 cm (- 222 N = k ( m) + F; Im 100 cm -)) + F; Rearrange above equation. k+ 2F; = 444 .. (3) On solving above two equations (2) and (3), we get F; = 48 N and k = 348 N/m Substitute 48 N for F¡ and 348 N/m for k in equation (1) F = (348 N/m) x + (48 N) The equation of line is F = 348x + 48
Transcribed Image Text:Concept Used: The linear relation of spring force, the displacement and the preload is, F = kx + F; .. (1) Calculation: Substitute 135 N for F and 25 cm for x in equation (1) 135 N = k (25 cm 135 N = k (4 m) + F; Im 100 cm )) + F; Rearrange above equation. k+ 4F; = 540 . (2) Substitute 222 N for F and 50 cm for x in equation (1) 222 N = k (50 cm (- 222 N = k ( m) + F; Im 100 cm -)) + F; Rearrange above equation. k+ 2F; = 444 .. (3) On solving above two equations (2) and (3), we get F; = 48 N and k = 348 N/m Substitute 48 N for F¡ and 348 N/m for k in equation (1) F = (348 N/m) x + (48 N) The equation of line is F = 348x + 48
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