10) Jason went outside to take the temperature twice during the day. If the temperature at 11:00 am was -4° and the temperature at 4:00 pm was 16°. What was the difference in temperature from 11:00 am to 4:00 pm?
10) Jason went outside to take the temperature twice during the day. If the temperature at 11:00 am was -4° and the temperature at 4:00 pm was 16°. What was the difference in temperature from 11:00 am to 4:00 pm?
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![**Problem:**
Jason went outside to take the temperature twice during the day. If the temperature at 11:00 am was \( -4^\circ \) and the temperature at 4:00 pm was \( 16^\circ \), what was the difference in temperature from 11:00 am to 4:00 pm?
**Solution Explanation:**
To find the difference in temperature, subtract the initial temperature from the final temperature:
1. Initial temperature at 11:00 am: \( -4^\circ \)
2. Final temperature at 4:00 pm: \( 16^\circ \)
The difference in temperature is calculated as:
\[
16^\circ - (-4^\circ) = 16^\circ + 4^\circ = 20^\circ
\]
Thus, the temperature increased by \( 20^\circ \) from 11:00 am to 4:00 pm.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F87571d09-94af-4a2a-a08b-b60f53da3b5a%2F81273ee9-2c66-4eb5-9429-9bda2ec3101f%2Fikz4u2j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem:**
Jason went outside to take the temperature twice during the day. If the temperature at 11:00 am was \( -4^\circ \) and the temperature at 4:00 pm was \( 16^\circ \), what was the difference in temperature from 11:00 am to 4:00 pm?
**Solution Explanation:**
To find the difference in temperature, subtract the initial temperature from the final temperature:
1. Initial temperature at 11:00 am: \( -4^\circ \)
2. Final temperature at 4:00 pm: \( 16^\circ \)
The difference in temperature is calculated as:
\[
16^\circ - (-4^\circ) = 16^\circ + 4^\circ = 20^\circ
\]
Thus, the temperature increased by \( 20^\circ \) from 11:00 am to 4:00 pm.
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