Jump to level 1airport_codes = {'Austin': 'AUS','San Jose': 'SJC','Washington': 'IAD','Houston': 'IAH','Dallas': 'DAL'}Type the program's outputprint (airport_codes.get('Dallas',print (airport_codes.pop('Dallas',print (airport_codes.get('Dallas',2'na'))'na'))'na'))3.

Algorithm: Define a dictionary named airport_codes with the given key-value pairs. Call the .get()…

Answered: Jump to level 1 Type the program's…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Jump to level 1
airport_codes = {
'Austin': 'AUS',
'San Jose': 'SJC',
'Washington': 'IAD',
'Houston': 'IAH',
'Dallas': 'DAL'
}
Type the program's output
print (airport_codes.get('Dallas',
print (airport_codes.pop('Dallas',
print (airport_codes.get('Dallas',
2
'na'))
'na'))
'na'))
3.

Expert Solution

Step 1

Algorithm:

Define a dictionary named airport_codes with the given key-value pairs.
Call the .get() method on the airport_codes dictionary to retrieve the value associated with the key 'Dallas', with a default value of 'na' in case the key is not found. Print the returned value to the console.
Call the .pop() method on the airport_codes dictionary to remove the key-value pair associated with the key 'Dallas', with a default value of 'na' in case the key is not found. Print the returned value to the console.
Call the .get() method again on the airport_codes dictionary to retrieve the value associated with the key 'Dallas', with a default value of 'na' in case the key is not found. Print the returned value to the console.

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