John kicks the ball and ball does projectile motion with an angle of 53° to horizontal. Its initial velocity is 10 m/s, find the maximum height it can reach, horizontal displacement and total time required for this motion.
John kicks the ball and ball does projectile motion with an angle of 53° to horizontal. Its initial velocity is 10 m/s, find the maximum height it can reach, horizontal displacement and total time required for this motion.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please use the formulas in the second picture.
Please write known and unknown like y = ?, x = ?, etc. too and show work in an easy to understand way.
![2. John kicks the ball and ball does projectile motion with an angle of 53°
to horizontal. Its initial velocity is 10 m/s, find the maximum height it can
reach, horizontal displacement and total time required for this motion.
© Copyright
www.physicstuto
V=10m/s
h=?
530
trotal=?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5c41678c-411a-4a7a-bcd7-17383604886b%2F349da3cc-1483-47aa-898d-fa5f3deccef8%2Fs5ipthe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. John kicks the ball and ball does projectile motion with an angle of 53°
to horizontal. Its initial velocity is 10 m/s, find the maximum height it can
reach, horizontal displacement and total time required for this motion.
© Copyright
www.physicstuto
V=10m/s
h=?
530
trotal=?
![Projectile Motion, Constant Accel. Formulas
X components (horizontal):
projectile:
Vx =Vx0 + a,t
X = X, + Vxot + ½ a,t?
v,? = V,0² + 2a,(x-x)
Vy =Vx0
X
X = X, + Vxot
v,? = v,
%D
2
x0
Y components (vertical):
projectile:
Vy = Vyo + a,t
y = yo + Vyot + ½ a,t²
v, = v,² + 2a,(y-y.)
Vy = Vyo - gt
y = yo + Vyot - ½ gt?
v, = v,² -
2g(y-yo)
= V.
= V.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5c41678c-411a-4a7a-bcd7-17383604886b%2F349da3cc-1483-47aa-898d-fa5f3deccef8%2Fj647jq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Projectile Motion, Constant Accel. Formulas
X components (horizontal):
projectile:
Vx =Vx0 + a,t
X = X, + Vxot + ½ a,t?
v,? = V,0² + 2a,(x-x)
Vy =Vx0
X
X = X, + Vxot
v,? = v,
%D
2
x0
Y components (vertical):
projectile:
Vy = Vyo + a,t
y = yo + Vyot + ½ a,t²
v, = v,² + 2a,(y-y.)
Vy = Vyo - gt
y = yo + Vyot - ½ gt?
v, = v,² -
2g(y-yo)
= V.
= V.
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