Jim Mead is a veterinarian who visits a Vermont farm to examine prize bulls. In order to examine a bull, Jim first gives the animal a tranquilizer shot. The effect of the shot is supposed to last an average of 65 minutes, and it usually does. Howeves Jim sometimes gets chased out of the pasture by a bull that recovers too soon, and other times he becomes worried about prize bulls that take too long to recover. By reading journals, Jim has found that the tranquilizer should have a mean duration time of 65 minutes, with a standard deviation of 15 minutes. A random sample of 6 of Jim's bulls had a mean tranquilized duration time of close to 65 minutes but a standard deviation of 27 minutes. At the 1% level of significance, is Jim justified in the claim that the variance is larger than that stated in his journal? (a) What is the level of significance? State the null and alternate hypotheses. OH ² 2251 H₂ ²225 OH ²2251 M₁ 0² 225 OH ² 2251 M₂:0² > 225 OH: 0²225: M₁: 0²225 (b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.) What are the degrees of freedom? What assumptions are you making about the original distribution? O We assume a uniform population distribution. We assume a exponential population distribution. O We assume a normal population distribution. We assume a binomial population distribution. (c) Find or estimate the P-value of the sample test statistic. OP-value> 0.100 O 0.050 P-value < 0.100 O 0.025 P-value < 0.050 O 0.010< P-value < 0.025 O 0.005 < P-value < 0.010 OP-value < 0.005
Jim Mead is a veterinarian who visits a Vermont farm to examine prize bulls. In order to examine a bull, Jim first gives the animal a tranquilizer shot. The effect of the shot is supposed to last an average of 65 minutes, and it usually does. Howeves Jim sometimes gets chased out of the pasture by a bull that recovers too soon, and other times he becomes worried about prize bulls that take too long to recover. By reading journals, Jim has found that the tranquilizer should have a mean duration time of 65 minutes, with a standard deviation of 15 minutes. A random sample of 6 of Jim's bulls had a mean tranquilized duration time of close to 65 minutes but a standard deviation of 27 minutes. At the 1% level of significance, is Jim justified in the claim that the variance is larger than that stated in his journal? (a) What is the level of significance? State the null and alternate hypotheses. OH ² 2251 H₂ ²225 OH ²2251 M₁ 0² 225 OH ² 2251 M₂:0² > 225 OH: 0²225: M₁: 0²225 (b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.) What are the degrees of freedom? What assumptions are you making about the original distribution? O We assume a uniform population distribution. We assume a exponential population distribution. O We assume a normal population distribution. We assume a binomial population distribution. (c) Find or estimate the P-value of the sample test statistic. OP-value> 0.100 O 0.050 P-value < 0.100 O 0.025 P-value < 0.050 O 0.010< P-value < 0.025 O 0.005 < P-value < 0.010 OP-value < 0.005
Related questions
Question
Transcribed Image Text:Jim Mead is a veterinarian who visits a Vermont farm to examine prize bulls. In order to examine a bull, Jim first gives the animal a tranquilizer shot. The effect of the shot is supposed to last an average of 65 minutes, and it usually does. However, Jim sometimes gets chased out of the pasture by a bull that recovers too soon, and other times
he becomes worried about prize bulls that take too long to recover. By reading journals, Jim has found that the tranquilizer should have a mean duration time of 65 minutes, with a standard deviation of 15 minutes. A random sample of 6 of Jim's bulls had a mean tranquilized duration time of close to 65 minutes but a standard deviation of 27
minutes. At the 1% level of significance, is Jim justified in the claim that the variance is larger than that stated in his journal?
(a) What is the level of significance?
State the null and alternate hypotheses.
O Ho: 0²225: H₁: o² = 225
O Ho: o² = 225; H₁:0² < 225
O Ho: 0² = 225; H₁:0² > 225
O Ho: 0² = 225; H₁: 0² #225
(b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.)
What are the degrees of freedom?
What assumptions are you making about the original distribution?
O We assume a uniform population distribution.
O We assume a exponential population distribution.
O We assume a normal population distribution.
O We assume a binomial population distribution.
(c) Find or estimate the P-value of the sample test statistic.
OP-value > 0.100
O 0.050 < P-value < 0.100
O 0.025 < P-value < 0.050
O 0.010 < P-value < 0.025
O 0.005 < P-value < 0.010
O P-value < 0.005
(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis?
O Since the P-value > a, we fail to reject the null hypothesis.
O Since the P-value > a, we reject the null hypothesis.
O Since the P-value ≤ a, we reject the null hypothesis.
O Since the P-value ≤ a, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the application.
O At the 1% level of significance, there is insufficient evidence to conclude that the variance of the duration times of the tranquilizer is larger than stated in the journal.
O At the 1% level of significance, there is sufficient evidence to conclude that the variance of the duration times of the tranquilizer is larger than stated in the journal.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 4 steps
