Jeneen v A certain liquid X has a normal bolling polnt of 120.70 °C and a bolling potnt elevation constant K=2.07 °C-kg-mol. Calculate the bolling point of a solution made of 98.6g of Iron(III) chloride (FeCl) dissolved In 800. g of X. Round you answer to 5 significant digits. O°C
Jeneen v A certain liquid X has a normal bolling polnt of 120.70 °C and a bolling potnt elevation constant K=2.07 °C-kg-mol. Calculate the bolling point of a solution made of 98.6g of Iron(III) chloride (FeCl) dissolved In 800. g of X. Round you answer to 5 significant digits. O°C
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the Kf and Kb equations with electrolytes
Jeneen v
A certain liquid X has a normal boiling point of 120.70 °C and a bolling point elevation constant K,=2.07 °C-kg mol .Calculate the bolling point of a solutlon
made of 98.6g of iron(III) chloride (FeCl,) dissolved In 800. g of X.
Round you answer to 5 significant digits.
do
°C
x10
の
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Expert Solution

Step 1
Given : Normal boiling point of liquid X = 120.70 oC
Mass of solvent i.e liquid X = 800 g = 0.800 Kg (since 1 Kg = 1000 g)
And Mass of solute i.e FeCl3 = 98.6 g
Molar mass of FeCl3 = Atomic mass of Fe + Atomic mass of Cl X 3 = 55.845 + 35.5 X 3 = 162.345 g/mol.
Since mass = moles X molar mass
=> 98.6 = moles of FeCl3 X 162.345
=> Moles of FeCl3 = 0.60735 mol approx.
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