iv. Calculate the Gibbs free energy for the overall reaction. V. Write the standard cell notation for the overall reaction. vi. Calculate Keq for the spontaneous reaction.
iv. Calculate the Gibbs free energy for the overall reaction. V. Write the standard cell notation for the overall reaction. vi. Calculate Keq for the spontaneous reaction.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Need help with the last 3.
![4. For the pair of species given: [
a. Cobalt/Cobalt(II) (E° = -0.28 V) and lead/lead(II) (E° = -0.13 V)
b. Aluminum (E° = -1.66 V) and silver (E° = +0.80 V)
Write balanced half-reactions and the overall spontaneous reaction.
ii.
i.
Diagram the cell. Be a specific as possible including labeling
electrodes with their charges and names (anode and cathode),
showing the direction of electron flow in the circuit and showing the
direction of cation and anion flow in the salt bridge.
iii.
Calculate the cell potential for the overall reaction.
iv.
Calculate the Gibbs free energy for the overall reaction.
V.
Write the standard cell notation for the overall reaction.
vi.
Calculate Keq for the spontaneous reaction.
E: -0.98V
b.
Alemimicrm
: - |-GGV
Pb/pb(11)
E : -0-18V
Silvarn
: +Q.80V
ー-CCN
maderetion potaontial
The alaetinode having gmoatom E valua will be
roduced and the lassam E value will be oxidised
+ 0.80
Gaidation potantial
maduetion potantial of silvar, EAgIng
- 0-80V
Raduetion
Baidation
The dactnada havimg groata E Yalue nil be maduced
Half eall maetion,
Ening > ExPAL
Cocidation
vorHompab
Half eall mmetion,
caidation
Reduetion
Oveenall maoction,
Gaidation
co(8) + PB
Ca)+PbC8)
→以 C)+ 0
Caq)
For a maetion to be spontenadus,
Raduetion
4G - -Ve and
Eell +ve
aquation©xB + aguation -
Eall
A Co)+ BAg)
-018-(-0,98)
-0.19 +0.28
Eall
(29-1-)- 080ー
-0.80 +1- GG
4G- -ve
The meactan ib spontamlous
:. 4G = -ve
Givan
- -O.18 V
Alusmigium CE.-1-6EV) sikyem (E-+a 8aV)
4G - -MFEall
AG: gibbs firoa an
Mi mumbon of alaetmom
Fi faraday
Eau Call potantiad
e Eal s tve, tham
4G - -mF (tve) e
the moaetion io Bpontamaws](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1da2b7e6-ff1f-4d03-afb3-6b710fedc971%2F91da5d6c-4c35-4b0b-82e7-d486bcf0cc27%2Fgeg2wzq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4. For the pair of species given: [
a. Cobalt/Cobalt(II) (E° = -0.28 V) and lead/lead(II) (E° = -0.13 V)
b. Aluminum (E° = -1.66 V) and silver (E° = +0.80 V)
Write balanced half-reactions and the overall spontaneous reaction.
ii.
i.
Diagram the cell. Be a specific as possible including labeling
electrodes with their charges and names (anode and cathode),
showing the direction of electron flow in the circuit and showing the
direction of cation and anion flow in the salt bridge.
iii.
Calculate the cell potential for the overall reaction.
iv.
Calculate the Gibbs free energy for the overall reaction.
V.
Write the standard cell notation for the overall reaction.
vi.
Calculate Keq for the spontaneous reaction.
E: -0.98V
b.
Alemimicrm
: - |-GGV
Pb/pb(11)
E : -0-18V
Silvarn
: +Q.80V
ー-CCN
maderetion potaontial
The alaetinode having gmoatom E valua will be
roduced and the lassam E value will be oxidised
+ 0.80
Gaidation potantial
maduetion potantial of silvar, EAgIng
- 0-80V
Raduetion
Baidation
The dactnada havimg groata E Yalue nil be maduced
Half eall maetion,
Ening > ExPAL
Cocidation
vorHompab
Half eall mmetion,
caidation
Reduetion
Oveenall maoction,
Gaidation
co(8) + PB
Ca)+PbC8)
→以 C)+ 0
Caq)
For a maetion to be spontenadus,
Raduetion
4G - -Ve and
Eell +ve
aquation©xB + aguation -
Eall
A Co)+ BAg)
-018-(-0,98)
-0.19 +0.28
Eall
(29-1-)- 080ー
-0.80 +1- GG
4G- -ve
The meactan ib spontamlous
:. 4G = -ve
Givan
- -O.18 V
Alusmigium CE.-1-6EV) sikyem (E-+a 8aV)
4G - -MFEall
AG: gibbs firoa an
Mi mumbon of alaetmom
Fi faraday
Eau Call potantiad
e Eal s tve, tham
4G - -mF (tve) e
the moaetion io Bpontamaws
![i.
Kos of ation
E flong of amion
halt bmidge
eloctmon flos
eathade
amade
love of Gation
e flow of amion
eathade
amode
halt bridgs
oleetmon
ACS) A +3e
Ag +eAg
Valtie eell
(8) +9e
Ovanall eall potontial, Eell Ecathode- Eamode
E call : Emad - Ezi
-0-80-(-1-66)
Voltie call
ii.
Ovamall esll potantial Eaal Ecathent Ex
: Eeal Emod - Eri
-013-(-0.98)
- - O-19+0.28
Ovanall ell poantial is tO-16V
+ @-86V
Ovamall ell potamtial is +0.86V
*+0. 16 V
:.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1da2b7e6-ff1f-4d03-afb3-6b710fedc971%2F91da5d6c-4c35-4b0b-82e7-d486bcf0cc27%2Fhagyqje_processed.jpeg&w=3840&q=75)
Transcribed Image Text:i.
Kos of ation
E flong of amion
halt bmidge
eloctmon flos
eathade
amade
love of Gation
e flow of amion
eathade
amode
halt bridgs
oleetmon
ACS) A +3e
Ag +eAg
Valtie eell
(8) +9e
Ovanall eall potontial, Eell Ecathode- Eamode
E call : Emad - Ezi
-0-80-(-1-66)
Voltie call
ii.
Ovamall esll potantial Eaal Ecathent Ex
: Eeal Emod - Eri
-013-(-0.98)
- - O-19+0.28
Ovanall ell poantial is tO-16V
+ @-86V
Ovamall ell potamtial is +0.86V
*+0. 16 V
:.
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