It would be appropriate to use the normal approximation to the binomial distribution in a situation with a sample of n = 20 and a population proportion of p- 80. O True False
Q: None
A: Solution:If the null hypothesis is true, most of the correlation values will be around 0.When the…
Q: A poll of 2,173 randomly selected adults showed that 86% of them own cell phones. The technology…
A: The question is about hypo. testing for popl. prop. Given : Test for p p = 0.93 vs p ≠ 0.93 X : 1865…
Q: 1. True or False: If your alternative hypothesis is “not equal to”, then you will have a one-tailed…
A: 1.If the alternative hypothesis states any direction (< or >), then the test is one-tailed…
Q: Single adults: According to a Pew Research Center analysis of census data, in 2012, 20% of American…
A: The provided information is The sample proportion is p=0.20 The sample size is n=25 the unusual to…
Q: . What is the test statistic? Z= C. What is the p value?
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Q: If random samples, each with n = 4 scores, are selected from a normal population with μ = 80 and σ =…
A: Given, Sample size = 4 Mean = 80 Standard deviation = 10 The objective is to find the standard…
Q: Suppose we want to test the null hypothesis H0 : p = 0.34 against the alternative hypothesis H1 : p…
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Q: Consider 232 binomial trials with 75 successes. (a) Is it appropriate to use a normal distribution…
A: Given, The binomial experiment, n = 232 p^=75232=0.3232 α=0.05 Z0.025=1.96
Q: If a distribution is normal with μ = 10 and σ = 5, what is the z score of 20?
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Q: Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a…
A: The sample size is 10, sample mean is 5.38, population mean is 5, and population standard deviation…
Q: A.) Compute the z value of the sample test statistic. (Enter a number. Round your answer to two…
A: Given : n=10 , X-bar=5.38% , σ=1.8% , μ0=4.5% , α=0.01 Here , we want to find the value of test…
Q: I only need assistance with parts A and B. Let x be a random variable representing dividend yield…
A: a) Given that α = 0.01. Hence, the level of significance is 0.01. Hypothesis: Null Hypothesis:…
Q: 1. The random variable is: A. X= number of accidental drowning people in one year. B. X= number of…
A: Since, you have asked multiple questions , we will solve the first question for you. If you want a…
Q: approximating normal distribution
A: we can solve this example step by step
Q: Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a…
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Q: Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a…
A: Given : x¯ = 5.38 σ = 2.0 μ = 4.7 n = 10 a. level of significance = 0.01 H0 : μ = 4.7 Ha : μ >…
Q: Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a…
A: From the provided information, Sample size (n) = 10 Sample mean (x̄) = 5.38% Standard deviation (σ)…
Q: How would I solve this problem?
A: a).the level of significance is 0.01 (1%).Null hypothesis:H0: µ=4.9%.Alternative hypothesis:H1:…
Q: Suppose that one in six smartphone users have fallen prey to cyber-attack. We use a sample of 190…
A: Given data: Suppose that one in six smartphone users have fallen prey to cyber-attack. i.e…
Q: If, in a sample of n = 25 selected from a normal population, X-53 and 5-5, what are the critical…
A: sampke size(n)=25mean(x)=53standard deviation(s)=5significance level(α)=0.05The null and alternative…
Q: Explain a situation in which the criteria for using the approximation would be met, ie. np ≥ 5 and…
A: Ans . The mean μ of a binomial = np. The standard deviation of a binomial = √np(1−p) For a normal…
Q: Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a…
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Q: I only need assistance with part D. A random sample of 50 binomial trials resulted in 20…
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Q: A poll of 2,136 randomly selected adults showed that 88% of them own cell phones. The technology…
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Q: The claim that the variance of a normal population is σ2 = 4 is to be rejected if the variance of a…
A: Given: Sample size (n) = 9 Population variance = = 4 Point at which the claim is rejected = s2…
Q: suppose a random sample of size 53 is selcted from a population with standard deviation of 12. find…
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Q: For any normal distribution, the probability of randomly selecting a z-score less than z = 1.40 is p…
A: The probability of randomly selecting a z-score less than z=1.40
Q: A population has a mean of 12 and a standard deviation of 5. A random sample of 200 is selected. The…
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Q: In a recent survey, approximately 90% of U.S. adults own a cell phone. Let's assume this can be…
A: Given Information : In a recent study , approximately 90% of US adults own a cell phone . Lets…
Q: A poll of 2,079 randomly selected adults showed that 90% of them own cell phones. The technology…
A: Test of p=0.93 vs p≠0.93 Sample X N Sample p 95% CI Z-Value P-Value 1 1876 2079 0.902357…
Q: poll of 2,134 randomly selected adults showed that 89% of them own cell phones. The technology…
A: (a) **State the null and alternative hypotheses:**- The null hypothesis (H0) is a statement of no…
Q: Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a…
A: Population mean = 4.4 Sample Mean = 5.38 Sample Size =10 Population SD = 2.8 Significance level =…
Q: You wish to test the following claim (H.) at a significance level of a = .02. H.:p = 0.59 Hap > 0.59…
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Q: Let x be a random variable representing the starting salary of a first-year teacher in a city. A…
A: Given that Sample size n =20 Sample mean=51425 Standard deviation =3549
Q: uppose we have a binomial experiment in which success is defined to be a particular quality or…
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Q: Using the same p=.80 from number one. Assume you have 1000 dogs and you want to determine the…
A: (a) Here, the sample size is larger. That is, n=1000. Hence, use a normal approximation to a…
Q: Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a…
A: Given Information : Let x be a random variable representing dividend yield of bank stocks. We may…
Q: Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a…
A: Given : Claim : The average yield for bank stocks is higher than that of the entire stock market.
Q: I need help with c and d. I keep getting a high z score
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Q: For a binomial distribution with p = .25 and n = 48, what is the z-score corresponding to X = 15?…
A: Given that n = 48 , p = 0.48 , at X = 15
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- Let x be a random variable representing the starting salary of a first-year teacher in a city. A report claims that the mean starting salary of these first-year teachers is greater than $50,000. To test this claim we find that a random sample of 20 teachers has a mean starting salary of $51,425 with a sample standard deviation of $3,549. If you assume that the population mean is $50,000, find the P-value corresponding to the hypothesis that the mean starting salary of the first-year teachers is greater than $50,000.Given a normal distribution with (Greek mu)=50 and (Greek sigma)=5, if you select a sample of n=100, what is the probability that x is less than 47?. Ammeters produced by a manufacturer are marketed under the specification that the standard deviation of gauge readings is no larger than 0.2 amp. One of these ammeters was used to make 14 independent readings on a test circuit with constant current. If the sample variance of these 14 measurements is 0.068, and it is reasonable to assume that the readings are normally distributed. Find the approximate probability that the sample variance will exceed 0.068 if the true population variance is 0.04.
- Normal Distribution Problem: A certain component for the newly developed electronic diesel engine is considered to be defective if its diameter is less than 8 mm or greater than 10.5 mm. The distributions of the diameters of these parts is known to be normal with a mean of 9.0 mm and a standard deviation of 1.5 mm. If a component is randomly selected, what is the probability that it will be defective? Q: Do I add the Right and Left tails and that's my total probability of defectiveness? Or, Do I take the Normal.Dist (from Excel) to the left of 10.5 minus the N.D left of 8 for a total of .588852 probability that it will be defective (that's a lot)? Please help! And, thank you in advance!Solve normal distribution problem #11Given a normal distribution with μ=103 and σ=15, and given you select a sample of n=9, What is the probability that X is above 104.2?
- Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a normal distribution with ? = 2.5%. A random sample of 10 bank stocks gave the following yields (in percents). 5.7 4.8 6.0 4.9 4.0 3.4 6.5 7.1 5.3 6.1 The sample mean is = 5.38%. Suppose that for the entire stock market, the mean dividend yield is ? = 4.9%. Do these data indicate that the dividend yield of all bank stocks is higher than 4.9%? Use ? = 0.01. (c) Find (or estimate) the P-value. (Enter a number. Round your answer to four decimal places.) ?Sketch the sampling distribution and show the area corresponding to the P-value. (Select the correct graph.)If we know that a normal distribution has a mean of H- 100 with o 20, and if one score is randomly selected from this distribution, what is the probability that the score will have a value between X 100 and X 130? 0,8664 0 0.4332 O 0.9332 G0.0668The prices of a sample of books at University A were obtained by two statistics students. Then the cost of books for the same subjects (at the same level) were obtained for University B. Assume that the distribution of differences is Normal enough to proceed, and assume that the sampling was random. 1. Find the test statistic for this test. t = ___ (Round to two decimal places as needed.) 2. Find the p-value for this test. p-value = ____ (Round to three decimal places as needed.) 3. What is the conclusion for this test?
- A poll of 1004 teens aged 13 to 17 showed that 57% of them have made new friends online. Use a 0.01 significance level to test the claim that half of all teens have made new friends online. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. C Let p denote the population proportion of all teens aged 13 to 17 who have made new friends online. Identify the null and alternative hypotheses. Ho: P H₁: p (Type integers or decimals. Do not round.) Identify the test statistic. 2=0 (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There ▼sufficient evidence to the claim that half of all teens have made new friends online.A poll of 2,115 randomly selected adults showed that 87% of them own cell phones. The technology display below results from a test of the claim that 94% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p = 0.94 vs p *0.94 Sample X N 1 1844 2,115 Sample p 0.871868 95% CI (0.853147,0.890588) a. Is the test two-tailed, left-tailed, or right-tailed? Z-Value - 13.19 P-Value 0.000Which of the following is not one of the assumptions of the t-test for independent samples? The populations of raw scores form at least a roughly normal distribution. They can only be done on Tuesdays. There is homogeneity of variance. There are two independent samples of interval/ratioscores.