Explain a situation in which the criteria for using the approximation would be met, ie. np ≥ 5 and n(1 − p) ≥ 5, and yet you would decide not to use the normal distribution.
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Explain a situation in which the criteria for using the approximation would be met, ie. np ≥ 5 and n(1 − p) ≥ 5, and yet you would decide not to use the
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- A random sample of size 22 is taken from a normally distributed population. 'The mean of the sample is x= 14.4 with a standard deviation of s 3.8. Do you think the population mean is less than 16? Explain your answer.I'm not sure how to set up the problem and how the mean value zero and standard deviation are differentAssume that we have two normal distributions both with means 0 and standard deviations σ1 and σ2. If σ1 ≥ σ2, then which of P (0 ≤ x ≤ σ1) and P (0 ≤ x ≤ σ2) is bigger? Explain your answer.
- I need the answer as soon as possibleThis is a standard Normal Distribution application Problem. I want you to show me how they got the final answer by solving equation 1 and 2. See the attached solution. Question The weights of boxes of oranges are normally distributed such that 30% of them are greater than 4kgand 20% are greater than 4.53kg. Estimate the mean and standard deviation of the weights.Suppose an x distribution has mean μ = 2. Consider two corresponding x distributions, the first based on samples of size n = 49 and the second based on samples of size n = 81. (a) What is the value of the mean of each of the two x distributions? For n = 49, μ x = For n = 81, μ x = (b) For which x distribution is P( x > 2.5) smaller? Explain your answer. The distribution with n = 49 because the standard deviation will be smaller.The distribution with n = 81 because the standard deviation will be smaller. The distribution with n = 49 because the standard deviation will be larger.The distribution with n = 81 because the standard deviation will be larger. (c) For which x distribution is P(1.5 < x < 2.5) greater? Explain your answer. The distribution with n = 49 because the standard deviation will be larger.The distribution with n = 49 because the standard deviation will be smaller. The distribution with n = 81 because the standard deviation will be…
- You wish to test the following claim (Ha) at a significance level of a = 0.002. Ho: P1 = P2 Ha:P₁ > P2 = You obtain 48% successes in a sample of size n₁ = 790 from the first population. You obtain 43.9% successes in a sample of size n2 645 from the second population. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion. O…You take a simple random sample of size 25 from a very large population in which the true proportioni p=0.1. Which statement below best describes what you know about the sampling distribution of p? (0.1)(0.9) (a) H,-0.1; o,- the distribution is skewed right. 25 (0.1)(0.9). 25 (b) H,=0.1; o,=. ; the distribution is skewed left. (0.1)(0.9). (c) ,=0.1; o,= the distribution is approximately Normal. %3D 25 (0.1)(0.9) (d) , the distribution is not approximately Normal. 25 =0.1; we cannot use the formula o, (0.1)(0.9) ; the distribution is approximately Normal. 25 (e) =0.1; we cannot use the formula o,You take a simple random sample of size 25 from a very large population in which the true proportion is p = 0.1. Which statement below best describes what you know about the sampling distribution of p ? %3D Hp-hat 0.1; we cannot use the formula Op-hat = (0.1)(0.9) : the distribution is not approximately normal, 25 Hp-hat = 0.1; op-hat = (0.1)(0.9) : the distribution is skewed. 25 Hp-hat = 0.1; Op-hat = (0.10.9) ; the distribution is approximately normal. 25 Hn-hat = 0.1; we cannot use the formula op-hat = V (0.1)(0.9) 25 Op-hat ; the distribution is approximately normal. * Previous IMG 0218.jpeg Next Activa PAUSE PRT F12 F11 F10 F9 M3 PO UP F8 M2 HOME F7 M1 F6 INS F5 F4 M6 PO DN M4 DEL END
- Under what circumstances would a score that is 15 points above the mean be considered an extreme score? O when the population mean is much smaller than 15 O when the population standard deviation is much larger than 15 O when the population mean is much larger than 15 O when the population standard deviation is much smaller than 15Please help me with the following question.You wish to test the following claim (H) at a significance level of a = 0.05. Ho: P₁ = P2 Ha: P1 > P2 You obtain 58% successes in a sample of size n₁ = 790 from the first population. You obtain 48.6% successes in a sample of size n₂ = 276 from the second population. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = 1.552 x What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = 0.0603 x The p-value is... 03 less than (or equal to) a O greater than a This test statistic leads to a decision to... Oreject the null hypothesis O accept the null hypothesis O fail to reject the null hypothesis As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the first population proportion is…
