It is specified that a certain type of iron should contain 0.85 g of silicon per 100 g of iron (0.85%). The silicon content of each of 26 randomly selected iron specimens was determined, and the accompanying Minitab output resulted from a test of the appropriate hypotheses. Variable N Mean sil cont 26 0.8890 StDev 0.1809 SE Mean T 0.0355 1.10 P 0.28 (a) What hypotheses were tested? Hoi u = 0.85 Ha: μ < 0.85 Ο Ηγ: μ = 0.85 Ha μ > 0.85 Ο Ηγ: μ = 0.85 Ha: μ ± 0.85 Ho: μ > 0.85 Ha: μ = 0.85 a' Ηρ: μ < 0.85 H₂: M = = 0.85 (b) What conclusion would be reached for a significance level of 0.05, and why? Since the P-value is ---Select--- ✓ the significance level of 0.05, we would ---Select--- ✓ the null hypothesis. What conclusion would be reached for a significance level of 0.10, and why? Since the P-value is ---Select--- ☑ the significance level of 0.10, we would ---Select--- ✓ the null hypothesis.
It is specified that a certain type of iron should contain 0.85 g of silicon per 100 g of iron (0.85%). The silicon content of each of 26 randomly selected iron specimens was determined, and the accompanying Minitab output resulted from a test of the appropriate hypotheses. Variable N Mean sil cont 26 0.8890 StDev 0.1809 SE Mean T 0.0355 1.10 P 0.28 (a) What hypotheses were tested? Hoi u = 0.85 Ha: μ < 0.85 Ο Ηγ: μ = 0.85 Ha μ > 0.85 Ο Ηγ: μ = 0.85 Ha: μ ± 0.85 Ho: μ > 0.85 Ha: μ = 0.85 a' Ηρ: μ < 0.85 H₂: M = = 0.85 (b) What conclusion would be reached for a significance level of 0.05, and why? Since the P-value is ---Select--- ✓ the significance level of 0.05, we would ---Select--- ✓ the null hypothesis. What conclusion would be reached for a significance level of 0.10, and why? Since the P-value is ---Select--- ☑ the significance level of 0.10, we would ---Select--- ✓ the null hypothesis.
A First Course in Probability (10th Edition)
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
Transcribed Image Text:It is specified that a certain type of iron should contain 0.85 g of silicon per 100 g of iron (0.85%). The silicon content of each of 26 randomly selected iron specimens was determined, and the accompanying Minitab output
resulted from a test of the appropriate hypotheses.
Variable
N
Mean
sil cont
26
0.8890
StDev
0.1809
SE Mean
T
0.0355
1.10
P
0.28
(a) What hypotheses were tested?
Hoi u = 0.85
Ha: μ < 0.85
Ο Ηγ: μ = 0.85
Ha μ > 0.85
Ο Ηγ: μ = 0.85
Ha: μ ± 0.85
Ho: μ > 0.85
Ha: μ = 0.85
a'
Ηρ: μ < 0.85
H₂: M =
= 0.85
(b) What conclusion would be reached for a significance level of 0.05, and why?
Since the P-value is ---Select--- ✓ the significance level of 0.05, we would ---Select--- ✓ the null hypothesis.
What conclusion would be reached for a significance level of 0.10, and why?
Since the P-value is ---Select--- ☑ the significance level of 0.10, we would ---Select--- ✓ the null hypothesis.
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