It is proposed to place a cable on an existing pole line along the shore of a lake to connect two points on opposite sides. Land Route Submarine Route Length, miles First cost of cable per mile Annual maintenance per mile Interest on Investment 10 P40,000 P68,000 950 3,500 18% 18% Тахes 3% 3% Net salvage value per mile Life, years 12,000 22,000 15 15 Which is more economical? Use ROR, Future, Present and Annual Worth Method

It is proposed to place a cable on an existing pole line along the shore of a lake to connect two points on opposite sides. Land Route Submarine Route Length, miles First cost of cable per mile Annual maintenance per mile Interest on Investment 10 P40,000 P68,000 950 3,500 18% 18% Тахes 3% 3% Net salvage value per mile Life, years 12,000 22,000 15 15 Which is more economical? Use ROR, Future, Present and Annual Worth Method

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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12:42 PM 74 Coal 4 to 9 Natural gas Wind 4 to 10.5 8.6 4.8 to 9.1 8.2 4.5 to 15.5 8.8 Solar National average cost of electricity to residential custom- ers: 11e/kWh 46% utilizes coal and natural gas as the primary fuel source. What about the ethical aspects of the govemment's allow- ance for these plants to continue polluting the atmosphere with the emissions that may cause health problems for citizens and further the effects of global warming? What types of regulations, if any, should be developed for PEC (and other generators) to follow in the future? 3. You developed an interest in the LEC relation and the publicized cost of electricity of 10.27e/kWh for this year. You wonder if the addition of 60 MW of wind-sourced electricity will make any difference in the LEC value for this next year. You did learn the following: This is year 11 for LEC computation purposes 1-25 years i=5% per year Case Study E-5.052 billion kWh 57 LEC last year was 10.22 e/kWh (last year's breakeven cost to…
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Question 5 Cost data of a machine is shown in the following table with an annual rate of 12%. Calculate annual worth at end of year 2. M&O cost Retention Yr. Market Value per year O (First Cost) 55,000 35,000 45.000 20,000 47,500 3 15,000 50,000 2,000 53,500 O 63,256 O 69.289 O 68,476 O 67,854 Question 6 Use same cost data from last question and 12% annual rate of return. Calculate annual worth at end of Year 3. O 65,765 O 64,332 O 67,428 O 66.256 Question 7 Use the same cost data of the machine from the above 2 questions and 12% interest rate per year. What is the ESL of this machine? O 1 O 2 O 3 O 4
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QUESTION 3 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% Machine A Machine B Machine C First cost, $ 15,828 30000 10000 Annual cost, $/year Salvage value, s Life, years 8,753 6,000 4,000 4,000 5,000 1,000 Answer the below questions: A- AW for machine A= QUESTION 4 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% Machine A Machine B Machine C First cost, $ 15000 21,344 10000 Annual cost, $/year 8,314 6,000 4,000 Salvage value, $ Life, years 4,000 5,000 1,000 Answer the below questions: B- AW for machine B=
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i=10%
A solid-waste recycling plant is considering two types of storage bins. Use ROR evaluation and an MARR of 18% per year to determine which should be selected, Storage Bin First Cost, $ AOC, $ per Year Salvage Value, $ Life, Years -22,000 -4000 1800 3 -35,000 -2300 2600 6 Since Alis (Click to select) MARR of 18%, [Click to select) should be selected.
Q1).Using AW method compare between the following alternatives: Operating and maintenance Alt. F.C. Income at the Annual nd S.V. Useful life i. end of 2 yearIncome A 35000 3500 2800 7000 8 8% B. 32000 1500 4700 2500 8%
FIRST COST ANNUAL COST SALVAGE VALUE ANNUAL INTEREST RATE STUDY PERIOD Power Line 20,000 1,950.90/month × 12= 23,410.8/year Solar 25,000 X 7= 125,000+10,000= 135,000 3,000/year 0 3.5% 25 ALTERNATIVE A: A solar panel costs 25,000. 7 solar panels are needed in a company. The installation fee is 10,000 and will have a useful 25 years with no salvage value. The maintenance per year is 5,000. The annual interest rate for solar panel is 1.5%. 0 1.5% 25 ALTERNATIVE B: A new power line will cost 20,000, with power costs expected to be 1,950.90 per month. The annual increase rate of electric bill is about 3.5%. Which alternative should be selected on the basis of a future worth analysis? Illustrate the cash flow diagram. USE MS EXCEL IN COMPUTATION and SHOW THE SOLUTION PROPERLY.
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