QUESTION 5 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10%. First cost, $ Annual cost, $/year Salvage value, $ Life, years Machine A Answer the below questions: C-AW for machine C = 15000 15,083 4,000 Machine B 30000 6,000 5,000 Machine C 12,557 4,000 1,000

QUESTION 5 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10%. First cost, $ Annual cost, $/year Salvage value, $ Life, years Machine A Answer the below questions: C-AW for machine C = 15000 15,083 4,000 Machine B 30000 6,000 5,000 Machine C 12,557 4,000 1,000

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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Compare the alternatives below using AW and i = 10% per year D -350,000 -35,000 35,000 ∞ First Cost, $ Annual operating cost, $/year Salvage value, $ Life, years с -150,000 - 10,000 15,000 10
Please no written by hand
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10. Evaluate a combined cycle power plant on the basis of the PW method when the MARR is 12% per year. Pertinent cost data are as follows: Power Plant NOT (thousands of $) $13,000 15 years $3,000 $1,000 $200 $550 Investment cost Useful life Market value (EOY 15) Annual operating expenses Overhaul cost-end of 5th year Overhaul cost-end of 10th year
5.24 You and your partner have become very interested in cross-country motorcycle racing and wish to purchase entry-level equipment. You have identified two alternative sets of equipment and gear. Package K has a first cost of $160,000, an operating cost of $7000 per quarter, and a salvage value of $40,000 after its 2-year life. Package L has a first cost of $210,000 with a lower operating cost of $5000 per quarter, and an estimated $26,000 salvage value after its 4-year life. Which package offers the lower present worth analysis at an interest rate of 8% per year, compounded quarterly?
For th below two machines and based on AW analysis which machine we should select? MARR=10% Machine A Machine B 26612 12417 4135 Life, years 3 Answer the below question: B- the AW for machine B= First cost, $ Annual cost, $/year Salvage value, $ 140454 7170 infinite
Alternate x has first cost of$20000 an operating cost of$9000 per year and $5000salvage value after 8 year .alternate Y will cost $12,183 with an operating cost of$ 7,627 per year and a salvage value of$7,104 after4 year .at MARR of 0.12% per year find the pw of machine y?
I need the answer in 10 minutes please
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Marmara Processing Technologies Company wants to buy milling cutters in order to meet its increasing production needs. As a result of the studies, the data in the table below were found. According to these data, what will be the current cost of the annual operating expense parameter of alternative B? A Purchase Cost 10.000 12.000 Annual Operating Expense 1.500 1.700 Scrap Values 2.000 3.000 Economic Life 4 4 Capital Cost 10% 10%
A furniture company intends to evaluate whether they want to stick with th equipment (defender) or replace them with the new productive equipment (challenger). The details of the cost required are shown in Table Q3(b) below. Use an interest rate of 20% per year. Items Initial cost eight (8) years ago (RM) Market value (RM) Yearly handling cost (RM) Life time (year) Salvage value (RM) Defender Challenger 450,000 25,000 700,000 160,000 70,000 5 10 50,000 Use the replacement analysis to justify whether the existing equipment is required to be replaced with the new equipment. (ii) If the existing equipment (defender) could be sold in international market, determine how much is the minimum value of the defender so that the challenger could replace the defender now?
Question 3 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% Machine A Machine B Machine C First coșt, $ 22,356 30000 10000 Annual cost, $/year 8,673 6,000 4,000 Salvage value, S Life, years 4,000 5,000 1,000 Answer the below questions: A- AW for machine A= Selected Answer: O -24,525.26 Correct Answer: O -16,453 ± 19%