s Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (e, low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 15% per year, which alternative has the lower present worth? Method First Cost M&O Cost, per Year Salvage Value Life DOM $-200,000 $-40,000 $2,000 2 years The present worth for the DDM method is $2635271 The present worth for the LS method is $ The (Click to select) method is selected LS $-500,000 $-40,000 $21,000 4 years

s Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (e, low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 15% per year, which alternative has the lower present worth? Method First Cost M&O Cost, per Year Salvage Value Life DOM $-200,000 $-40,000 $2,000 2 years The present worth for the DDM method is $2635271 The present worth for the LS method is $ The (Click to select) method is selected LS $-500,000 $-40,000 $21,000 4 years

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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Investment Cost Useful Life 15 years Market Value, aka salvage value (EOY 15) 3,000 Annual Operating Expenses Overhaul cost--EOY 5 Overhaul cost--EOY10 ('000s of $) 13,000 $19,553,380. NO. 1,000 $19,210,488. YES 200 Evaluate a combined cycle power plant on the basis of the PW method when the MARR is 12% per year. Pertinent cost data are shown in the table. Should the plant be built? 550 $19,553,380. Impossible to say without additional information. O $19,210,488. Impossible to say without additional information.
Compare the alternatives shown on the basis of their capitalized costs using a MARR of 10% per year. Alternative First cost, $ Annual operating cost, $ per year Salvage value, $ Life, years M -155,000 -30,000 8,000 5 N -875,000 -11,000 1,000,000 00 The capitalized cost for alternative M is $- The best alternative selected on the basis of their capitalized costs is alternative M and the capitalized cost for alternative N is $-
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A large textile company is trying to decide which sludge dewatering process it should use ahead of its sludge drying operation. The costs associated with centrifuge and belt press systems are shown. Compare them on the basis of their annual worths using an interest rate of 10% per year. System First cost, $ Centrifuge -250,000 AOC, $/year -31,000 Overhaul in year 2, $ Salvage value, $ 40,000 Life, years 6 Belt Press -170,000 -35,000 -26,000 10,000 4 The annual worth of the centrifuge system is $- 76216 ✪, and the annual worth of the belt press system is $- 82283.7 The system selected on the basis of the annual worth analysis is the centrifuge system.
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Problem 05.017 Alternative Comparison - Different Lives Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (i.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 19% per year, which alternative has the lower present worth? Method First Cost M&O Cost, per Year Salvage Value Life DDM $-160,000 $-40,000 $10,000 2 years The present worth for the DDM method is $ The present worth for the LS method is $ The (Click to select) method is selected. LS $-500,000 $-10,000 $33,000 4 years
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5
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Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (i.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 8% per year, which alternative has the lower present worth?
A dyeing and finishing plant is interested in acquiring a dyeing machine for the production of a new product. Three alternatives are being considered assummarized below. Which alternative should be recommended if the plant’sMARR (hurdle rate) is 15% per year using (a) the IRR method and (b) the annual worth method?