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- The null hypothesis for a repeated-measures test states O cach individual will have a difference score of D-0 the overall sample will have a mean difference of Mo -0 O the entire population will have a mean difference of do -0 O Allof the other options are correctDandelions have effects on crop production and lawn growth and are studied. In one region, the mean number of dandelions per square meter was found to be 10.8.Find the probability of no dandelions in an area of 1 m².P(X=0)=P(X=0)= Find the probability of at least one dandelion in an area of 1 m².P(at least one) = Find the probability of at most two dandelions in an area of 1 m².P(X≤2)=P(X≤2)=Refer to the sample data for pre-employment drug screening shown below. If one of the subjects is randomly selected, what is the probability that the test result is a false positive? Who would suffer from a false positive result? Why? Pre-Employment Drug Screening Results Positive test result Negative test result Drug Use Is Indicated Drug Use Is Not Indicated Subject Uses Drugs 42 11 Subject Is Not a Drug User 2 29 The probability of a false positive test result is (Round to three decimal places as needed.) Who would suffer from a false positive result? Why? O A. The person tested would suffer because he or she would be suspected of using drugs when in reality he or she does not use drugs. B. The employer would suffer because the person tested would not be suspected of using drugs when in reality he or she does use drugs. C. The person tested would suffer because he or she would not be suspected of using drugs when in reality he or she does use drugs. D. The employer would suffer…
- Suppose there is a claim that a certain population has a mean, u, that is different than 7. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.10 level of significance. To start this test, you write the null hypothesis, Ho, and the alternative hypothesis, H, as follows. Ho: H=7 H: u#7 Suppose you also know the following information. The value of the test statistic based on the sample is - 1.845 (rounded to 3 decimal places). The p-value is 0.065 (rounded to 3 decimal places). (a) Complete the steps below for this hypothesis test. O Two-tailed Step 2: Enter the test statistic. (Round to 3 decimal places.) 0.3 Step 3: Shade the area represented by the p- value. 0.2 Step 4: Enter the p- value. (Round to 3 decimal places.) (b) Based on your answer to part (a), which statement below is true? Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. Since the…For each probability and percentile problem, draw the picture.A random number generator picks a number from 1 to 8 in a uniform manner. Part (e) ? = rounded to two decimal places) Part (f) P(3.5 < X < 7.25) = (Enter an exact number as an integer, fraction, or decimal.) Part (g) P(X > 3.67) = (rounded to two decimal places)5. Suppose a marketing research firm would like to examine if the social networking site that a person primarily uses is influenced by his or her age. In a randomly drawn sample, 337 social network users were asked which site they primarily visited. These data are presented in the following table along with each person's age group. Complete parts a. through c. below. Click the icon to view the data table. a. Using a = 0.025, perform a chi-square test to determine if age group and social networking site used are independent of one another. Identify the null and alternative hypotheses for a chi-square test of independence based on the information in the table. Choose the correct answer below. O A. Ho: Age group and social networking site are independent of one another. H1: The social networking site used affects the age group. O B. Ho: Age group and social networking site are independent of one another. H,: Age group and social networking site are not independent of one another. O C. Ho:…
- 5.How do I tell if I have a one-sample t-test or an indepenent-samples t-test in the following situation? I have a group that has received a financial benefit and were chosen to rate their happiness after receiving that benefit. However, all members, those in the sample and those in the total group received the same beneifit. Do I have two groups and need an independent samples t-test or do I have one group measured against the mean?A machine uses electrical switches that are known to have a 3% fail rate for each use. The machine uses three switches, and each switch is independent. (a) How many outcomes are there in the sample space? 8 (b) Let x = the number of failed switches in one run of the machine. How many possible values of x are there? 4 (c) What is the probability of exactly one switch failing in one run of the machine?. 0.0847 X There is more than one way for one switch to fail in one run of the machine. (d) If the probability of no switches failing is 0.912673 and the probability of all switches failing is 0.000027, then complete the probability distribution table for x. X p(x) 0.912673 0 Need Help? Read It 0.084681 1 ✓ 0.002619 2 0.000027 3
- A2 The sample space of an experiment is S={0,1,2.5,6}. All sample space elements have equal probability of occurrence. A random variable is defined as X=S+1. The mean value of random variable X is? A- 4.75 B- 2.5 C- 1.25 D- 3.382 of 4 (0 complete) Using the data given below, determine whether it would unusual for a household to have no HD televisions. The number of televisions (HD) per household in a small town Televisions 1 Households 26 445 655 1474 P(x) 0.010 0.171 0.252 0.567 Choose the correct answer below. O A. It would be unusual because the probability of having no HD televisions is less than 0.05. O B. It would not be unusual because the probability of having no HD televisions is more than 0.05. OC. It would not be unusual because 26 people have no HD televisions in the town. O D. It would be unusual because 26 people have no HD televisions in the town. Click to select your answer.Please help me with my statistics ? Thank you