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Let X be a standard normal random variable. Find the following probabilities: 1. P₁ = P(X> 0). 2. P₂ 3. P3 P(-1.18 < X <-0.59). = 4. P4P(0.59 ≤ x ≤ 1.18). P(-1.18 ≤ x ≤ 0).

Let X be a standard normal random variable. Find the following probabilities: 1. P₁ = P(X> 0). 2. P₂ 3. P3 P(-1.18 < X <-0.59). = 4. P4P(0.59 ≤ x ≤ 1.18). P(-1.18 ≤ x ≤ 0).

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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How were the answers of 0.5000, 0.3810, 0.1586, and 0.1586 attained?

Let X be a standard normal random variable. Find the following probabilities: 1. P₁ = P(X> 0). 2. P₂ = P(-1.18 < X < 0). 3. P3 P(-1.18 ≤X ≤ -0. 59). 4. P4P(0.59 ≤ x ≤ 1. 18). (P1, P2, P3, P4) = 0.5000,0.3810,0.1586,0.1586
Transcribed Image Text:Let X be a standard normal random variable. Find the following probabilities: 1. P₁ = P(X> 0). 2. P₂ = P(-1.18 < X < 0). 3. P3 P(-1.18 ≤X ≤ -0. 59). 4. P4P(0.59 ≤ x ≤ 1. 18). (P1, P2, P3, P4) = 0.5000,0.3810,0.1586,0.1586
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