It is determined that the results of mesh current equations from above are as follows: I₁ = 3.3A;, I₂ = = - - 0.064A;, I3 = - - 0.79A (Remember that this means I2 and I are actually going counter - clockwise) Using these results, calculate the following: a. The voltage (V4), with actual pot arity, across R4. b. The current (12), with actual direction, across R₂. Mesh equations are 31₁ = 12 + 013 = 10 - (11-1012 + 513 = 0 (011 + 512-813) = (6) R R R www www www 20 40 JON R 10 6V
It is determined that the results of mesh current equations from above are as follows: I₁ = 3.3A;, I₂ = = - - 0.064A;, I3 = - - 0.79A (Remember that this means I2 and I are actually going counter - clockwise) Using these results, calculate the following: a. The voltage (V4), with actual pot arity, across R4. b. The current (12), with actual direction, across R₂. Mesh equations are 31₁ = 12 + 013 = 10 - (11-1012 + 513 = 0 (011 + 512-813) = (6) R R R www www www 20 40 JON R 10 6V
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter29: Dc Generators
Section: Chapter Questions
Problem 5RQ: What are interpoles, and what is their purpose?
Related questions
Question
NEED HANDWRITTEN SOLUTION NOT USING CHAT GPT
![It is determined that the results of mesh
current equations from above are as
follows:
I₁ = 3.3A;, I₂ =
=
-
- 0.064A;, I3
=
-
- 0.79A
(Remember that this means I2 and I are
actually going counter - clockwise)
Using these results, calculate the
following:
a. The voltage (V4), with actual pot arity,
across R4.
b. The current (12), with actual direction,
across R₂.
Mesh equations are
31₁ = 12 + 013 = 10
-
(11-1012 + 513 = 0
(011 + 512-813) = (6)
R
R
R
www
www
www
20
40
JON
R 10
6V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F74cebf95-e587-4018-a3a7-bb4cbb8ace07%2F2af74293-0d13-40f6-9394-5297b71c3b24%2Far4wac7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:It is determined that the results of mesh
current equations from above are as
follows:
I₁ = 3.3A;, I₂ =
=
-
- 0.064A;, I3
=
-
- 0.79A
(Remember that this means I2 and I are
actually going counter - clockwise)
Using these results, calculate the
following:
a. The voltage (V4), with actual pot arity,
across R4.
b. The current (12), with actual direction,
across R₂.
Mesh equations are
31₁ = 12 + 013 = 10
-
(11-1012 + 513 = 0
(011 + 512-813) = (6)
R
R
R
www
www
www
20
40
JON
R 10
6V
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