It is defined as the ratio of rms load voltage and average load voltage of an alternating current. Your answer In electronics it is define as the ratio of the RMS (root mean square) value to the average value (mathematical mean of absolute values of all points on the waveform). Your answer By definition: It is the amount of rms value of ac component to the dc component in the rectifier output. Your answer It is defined as ratio of dc power available at the load to the input ac power. Your answer

It is defined as the ratio of rms load voltage and average load voltage of an alternating current. Your answer In electronics it is define as the ratio of the RMS (root mean square) value to the average value (mathematical mean of absolute values of all points on the waveform). Your answer By definition: It is the amount of rms value of ac component to the dc component in the rectifier output. Your answer It is defined as ratio of dc power available at the load to the input ac power. Your answer

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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a) Explain the operation of the controlled full-wave bridge rectifier shown in figure 3. b) The controlled full-wave bridge rectifier shown in figure 3 has a source 120 V rms at 60 Hz, R = 1092, L=20 mH, and a = 60°. Determine: i. An expression for the load current. ii. The average load current. iii. The power absorbed by the load. iv. Sketch the graph of the output waveform. Vs S₁ S4 Figure $3 $₂ Lo Vo
1. Build the following circuit. Use the function generator to obtain the specified AC input voltage. D4 D1 + RL 1.2K + VsN D3 Y D2 9V sin(2n 50 t) Verify the amplı, 'de and frequency of the output waveform on the load resistor, RL. Peak voltage: Waveform period: Frequency 1.d) How much power would have. en dissipated on the diodes in total, if the same output waveform was obtainea sing a full-wave rectifier with a center- tapped transformer?
The 3-phase half-wave diode rectifier feeds a load consisting of a 50-ohm resistor. The sinusoidal sources in the input of the rectifier are wye-connected and phase-to-phase rms voltage is 380 volts. Calculate the power (in watts) absorbed by the load. Assume the diode is ideal. a. 680.36 b. 2267.90 C. 4082.20 d. 1700.90 e. 1360.70
Consider a three-phase diode rectifier supplying a R = 10 Ω DC load. The supply systemis 440 VLL and 60 Hz. A) What is the value of the average (DC) current across the load?B) Compute the value of an inductive filter (L) to be added in series with the resistiveload to limit the rms value of the lowest order current harmonic to 1% of the DC currentvalue. Note: 2 /[( 1)( 1)] Vdch = Vdc0 h − h + (in rms).
3.16 A three-phase, full-wave half-controlled rectifier bridge circuit is operating at a delay angle a = 67° when supplying full power. The per-phase inductance of the coupled transformer is 2 mH. The input voltage has an rms magnitude of 230 V per phase at 50 Hz. The load current in the d.c. side is 15 A at 200 V. It is required to: (a) Obtain the drop in the d.c. voltage due to current overlap. (b) Calculate the rms secondary voltage of the transformer. (c) Calculate the overlap angle. (d) Obtain the recovery angle while the converter in operating in the inversion mode with 15 A, 200 V d.c. input. (e) Obtain the firing angle for the conditions in (d). [Ans: (a) 4.5 V, (b) 450 V, (c) 1.06°, (d) 67.14°, (e) 111.8°]
A full-wave rectifier operating from the 60-Hz ac supply produces a 20-V peak rectified voltage. If a 200-uF capacitor is used, calculate the ripple at a load of 120 mA. Ripple- 1.44 A Full wave rectifier operating from the 60Hz ac supply produces a 20-V rectified voltage. If a 200-uF capacitor is used, calculate the ripple at a load of 120 mA
While constructing a Bridge rectifier, the designer mistakenly has swapped the terminals of D3 as shown in the figure below, where • Diode D3 is damaged so that it is always open circuit regardless of the applied voltage. • vs(t) is a sinusoidal signal with a peak value (Vs = 5 V). • Diodes are modelled using the constant voltage model with VDO = 0.7 V • The ac line voltage has an rms value of 120 V and a frequency (f) = 60 Hz • The resistance RL = 10 kohm. a) Calculate the transformer turns ratio (N1/N2) if vs(t) is obtained from the secondary side of the transformer whose primary side is connected to the ac line voltage (which has a 120 V rms value). b) Plot in the same graph the input signal vs(t) and the output signal vout(t) (show all details including amplitudes, time instances, etc.) Please plot the graph. c) Calculate the rms values of the output signal vout(t). (hint: sin2 (x) = 0.5(1- cos(2x))) d) If a capacitor C = 3.58 µF is connected across R = 10 kohm, repeat (b) in a new…
Q1)Design moving coil ammeter as a voltmeter to read 15 V (RMS) alternating voltage. If the internal resistance of the ammeter is 5 KQ , the voltage across the internal resistance is 0.5 v and the resistance of the diodes in the forward direction is 1 KQ, find the multiplier resistance and sensitivity . Assume half wave rectification and a shunt resistance across the meter. The value of the shunt resistance across the ammeter is 2.5 KQ. Q2) Re-design the question above for full wave rectifier (without Rsh)
. A half-wave rectifier is needed to supply 15-V dc to a load that draws an average current of 300 mA. The peak-to-peak ripple is required to be 0.2 V or less. What is the minimum value allowed for the smoothing capacitance?
Which of the following statements about bridge tip rectifiers is false? A) If the 1-phase type has source inductance, the average value of the output voltage is lower than in the absence of the inductance. B) The average output voltage value of the 1-phase type is 0.9 times the peak voltage of the network. C) none D) There are only odd harmonics in the current drawn by the 1-phase type from the mains. E) The average value of the output voltage of the 3-phase type is larger as the 3-phase and 1-phase types are compared
Consider the full-wave rectifier circuit shown below, where• vS(t) is a sinusoidal signal with a peak value (Vs = 5 V).• Diodes are modelled using constant voltage model with VDO = 0.7 V• The ac line voltage has an rms value of 120 V and a frequency (f) = 60 Hza) Calculate the transformer turns ratio. b) Plot in the same graph signal vS(t) and the output signal vO(t) versus time (t) (show all details including amplitudes, time instances, etc.) c) Calculate the rms value of the output signal vO(t). (hint: sin2(x) = 0.5(1- cos(2x))) d) If a capacitor C=3.58 F is connected across R = 10 k, repeat (b) in a new graph
The input to a 3-phase full-wave rectifier is 60 Hz AC voltage. If the voltage drop across diodes is 0 V, The RMS voltage at the load would be: O A. None of the other choices are correct O B. Cannot tell until we have more information O C. Lower than the RMS voltage at the input O D. Higher than the RMS voltage at the input O E. The same as the RMS voltage at the input