Q: A single-phase full-wave uncontrolled bridge rectifier is supplying a highlyinductive load (L/R ratio is very large), the load current is assumed to be smooth and ripple -free. If the supply voltage is 220V, 50HZ, and the inductor load resistance R=22 2, Calculate:(a)The average output voltage Vdc and current Idc.(b) The rms value of the output voltage Vorms and current Iorms .(c) The rms value of the diode current IDrms and the PRV of each diode.

Q: Consider the half-wave rectifier shown below.  It needs to deliver 0.1 A and an average of 15 V to a…

A:

Q: 3 A peak rectifier (peak follower) Cir cuit is given below. Vs is a GOH3 Sinusuidal Vollage with…

A: Given data,  Vp=50 Vf=60 HzR=5 kΩVr=2 V

Q: a-Draw the cct Q1/(A) For the waveforms of s phase angle control Ac-Ac converter: - diagram and…

A: the concepts and approaches to solve them effectively.**Q1(A) Single-Phase Half-Wave AC-DC…

Q: The Circuit Below shows a basic Buck-Boost Converter with a highly inductive Load. With a Deliberate…

A: In the given circuit firstly we have to find the duty cycle Duty cycle = 0.55+17×0.2100Duty cycle…

Q: A half-wave rectifier is needed to supply 15 VDC to a load that draws an average current of 250 mA.…

A: I hope this is helpful If you have any doubt you can ask me

Q: The full wave rectifier in the circuit below is to deliver 0.25A and 15V (peak) to a load. The…

A: Given data: IDC=0.25 AVL=15 VVp=120 VVγ=0.7 VVp-p=0.4 V

HVDC

HVDC stands for high voltage direct current in the electric power transmission system. The high voltage direct current system uses direct current (DC) for the transmission of electrical power through transmission lines in contrast with the alternating current that is the AC system. The HVDC is used to transmit bulk power point-to-point through long distances transmission lines. Power is rapidly transferred because the efficiency of transmission lines is greatly increased over long distances due to HVDC lines.