Is this a Phone Number?

Learning Objectives

In this lab, you will

Create a function according to the specifications
Use nested if/else statements

Instructions

Write a function, isPhoneNumber(digits), that checks to see if the input is a real phone number. This function should:

Return True if 'digits' is type int and is 10 digits long
Otherwise, returns False

You can use the assert statements to test that your function behaves as expected.

Hint: You can confirm 'digits' is an int with type(digits) == int

Hint: To check the length of the number, you can convert it to a string first, then check the length. Alternatively, you can use integer division.

# Define the function isPhoneNumber() below. The function should:
# - Check that the input value has type 'int' and is 10 digits long.
# - If this is true, return True
# - If this is false, return False
def isPhoneNumber(digits):
pass



# No print statement is needed for submission, but you can use a print statement to
# confirm the output of isPhoneNumber(digits) is as expected with various inputs .
if __name__ == "__main__":
assert isPhoneNumber("1234567890") == False
assert isPhoneNumber(1234567890) == True

1: Test isPhoneNumber(4243137890) returns True ^
0/1
Test isPhoneNumber(4243137890) returns True
Test feedback
isPhoneNumber (4243137890) incorrectly returned None
2: Test isPhoneNumber(3109216754) returns True ^
0/1
Test isPhoneNumber(3109216754) returns True
Test feedback
isPhoneNumber (3109216754) incorrectly returned None
3: Test isPhoneNumber(243137890) returns False ^
0/1
Test isPhoneNumber(243137890) returns False
Test feedback
isPhoneNumber (243137890) incorrectly returned None
4: Test isPhoneNumber('sandwiches') returns False a
0/1
Test isPhoneNumber('sandwiches') returns False
Test feedback
isPhoneNumber ('sandwiches') incorrectly returned None

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions