irin. Polyté that dissolves in chloroform is culate the vapor pressure of the solution at 25 °C when 8.475 grams of aspirin, C,H3O, (180.1 g/mol), are dissolved in .0 grams of chloroform. proform = CHCl = 119.40 g/mol.

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**Understanding Vapor Pressure with Chloroform and Aspirin Solution**

The vapor pressure of chloroform is 173.11 mm Hg at 25 °C. Chloroform is a nonvolatile, nonelectrolyte solvent in which aspirin can dissolve.

**Objective:** 
Calculate the vapor pressure of a solution at 25 °C when 8.475 grams of aspirin (C₉H₈O₄, molar mass = 180.1 g/mol) are dissolved in 237.0 grams of chloroform.

**Data Provided:**

- Molar Mass of Chloroform (CHCl₃): 119.40 g/mol
- Initial Vapor Pressure of Chloroform: 173.11 mm Hg

**Steps:**

1. **Find the Moles of Solute and Solvent:**
   - Calculate the moles of aspirin (C₉H₈O₄) using its given mass and molar mass.
   - Calculate the moles of chloroform (CHCl₃) using its given mass and molar mass.

2. **Use Raoult's Law to Find the Vapor Pressure of the Solution:**
   - Apply the formula: VP(solution) = χ₁ * VP₀
     - Where χ₁ is the mole fraction of the solvent and VP₀ is the vapor pressure of the pure solvent.

3. **Solve for the Vapor Pressure of the Solution:**
   - Determine the mole fraction of chloroform in the solution.
   - Multiply the mole fraction of chloroform by its pure vapor pressure to get the solution's vapor pressure.

This calculation demonstrates how solutes affect the vapor pressure of solvents, an important concept in physical chemistry related to colligative properties.

**Submit Answer:**
Use the information to find the corrected vapor pressure of the solution. You may retry up to nine more times.

No graphs or diagrams are present in this section.
Transcribed Image Text:**Understanding Vapor Pressure with Chloroform and Aspirin Solution** The vapor pressure of chloroform is 173.11 mm Hg at 25 °C. Chloroform is a nonvolatile, nonelectrolyte solvent in which aspirin can dissolve. **Objective:** Calculate the vapor pressure of a solution at 25 °C when 8.475 grams of aspirin (C₉H₈O₄, molar mass = 180.1 g/mol) are dissolved in 237.0 grams of chloroform. **Data Provided:** - Molar Mass of Chloroform (CHCl₃): 119.40 g/mol - Initial Vapor Pressure of Chloroform: 173.11 mm Hg **Steps:** 1. **Find the Moles of Solute and Solvent:** - Calculate the moles of aspirin (C₉H₈O₄) using its given mass and molar mass. - Calculate the moles of chloroform (CHCl₃) using its given mass and molar mass. 2. **Use Raoult's Law to Find the Vapor Pressure of the Solution:** - Apply the formula: VP(solution) = χ₁ * VP₀ - Where χ₁ is the mole fraction of the solvent and VP₀ is the vapor pressure of the pure solvent. 3. **Solve for the Vapor Pressure of the Solution:** - Determine the mole fraction of chloroform in the solution. - Multiply the mole fraction of chloroform by its pure vapor pressure to get the solution's vapor pressure. This calculation demonstrates how solutes affect the vapor pressure of solvents, an important concept in physical chemistry related to colligative properties. **Submit Answer:** Use the information to find the corrected vapor pressure of the solution. You may retry up to nine more times. No graphs or diagrams are present in this section.
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