When 105.g of glycine C2H5NO2 are dissolved in 1200.g of a certain mystery liquid X, the freezing point of the solution is 4.6°C lower than the freezing point of pure X. On the other hand, when 105.g of iron(III) chloride are dissolved in the same mass of X, the freezing point of the solution is 7.5°C lower than the freezing point of pure X. Calculate the van't Hoff factor for iron(III) chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits. i=
Since, nitrobenzene C2H5NO2 is non electrolyte it will be having vantoff factor 1
Now
Since mass of X is same,
∆Tf is directly proportional to
i×kf×no. Of moles /mass of X( in kg)
So, ∆Tf is directly proportional to i×Kf×no. Of moles
No. Of moles of C6H5NO2 = 105/123.11= 0.8528
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