umen OHMQ Video• Question 14IQ is normally distributed with a mean of 100 and a standard deviation of 15.Suppose one individual is randomly chosen. Let X- 1Q of an individual.(a) Find the z-score for an IQ of 123, rounded to three decimal places.1.533(b) Find the probability that the person has an IQ greater than 123.0.0630(C) Shade the area corresponding to this probability in the graph below. (Hint: Thex-axis is the z-score. Use your z-score from part (a), rounded to one decimal place).Shade: Right of a valueClick and drag the arrows to adjust the values.1.5(d) MENSA is an organization whose members have the top 2% of all IQs. Find theminimum IQ needed to qualify for the MENSA organization.69.25(e) Sketch the graph, and write the probability statement.Edit - Insert - Formats - B IYX xE I 3E-E-3 e P 2 A m-ΣΣν() The middle 50% of IQs fall between what two values?(g) Sketch the graph and write the probability statement.Edit- Insert- Formats - BI Y x x A- -Question Help: O Post to forumCalculatorSubmit Question

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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IQ is normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual is randomly chosen. Let X = 1Q of an individual. (a) Find the z-score for an IQ of 97, rounded to three decimal places. (b) Find the probability that the person has an IQ greater than 97. (c) Shade the area corresponding to this probability in the graph below. (Hint: The x-axis is the z- Score. Use your z-score from part (a), rounded to one decimal place). Shade: Left of a value Click and drag the arrows to adjust the values. -1 3 4 -1.5 (d) MENSA is an organization whose members have the top 2% of all IQs. Find the minimum IQ needed to qualify for the MENSA organization. (e) Sketch the graph, and write the probability statement. BIUX, x' C 次四 Edit. Insert - Formats - Σ ΣΗ
IQ is normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual is randomly chosen. Let X = X = IQ of an individual. (a) Find the z-score for an IQ of 123, rounded to three decimal places. 1.533 (b) Find the probability that the person has an IQ greater than 123. 0.0630 (c) Shade the area corresponding to this probability in the graph below. (Hint: The x-axis is the z-score. Use your z-score from part (a), rounded to one decimal place). Shade: Left of a valueRight of a valueBetween two values2 regions. Click and drag the arrows to adjust the values.
The one in the yellow is the previous tab.
Pulse rates of adult men are approximately normal with a mean of 70 and a standard deviation of 8. Which choice correctly describes how to find the proportion of men that have a pulse rate greater than 78? (a) Find the area to the right of z = -1 under a standard normal curve. (b) Find the area to the right of z=1 under a standard normal curve. (c) Find the area to the left of z = 1 under a standard normal curve. (d) Find the area between z=-1 and z=1 under a standard normal curve. (e) None of the above
From generation to generation, the mean age when smokers first start to smoke varies. However, the standard deviation of that age remains constant at around 2.1 years. A survey of 38 smokers of this generation was done to see if the mean starting age is at least 19. The sample mean was 18.1 with a sample standard deviation of 1.3. Do the data support the claim at the 5% level? (i) Alpha (Enter an exact number as an integer, fraction, or decimal.)? =
The graph to the right depicts IQ scores of adults, which are normally distributed with a mean of 100 and a standard deviation of 15. Find the indicated IQ score, labeled X on the graph, such that the area to the right of X is 0.65.
Suppose that average age at first marriage is 23.33 years old, with a standard deviation of 6.13. If one got married at 26 years old (X=26), how far (in standard deviations) is that person from the average age at first marriage? (Hint: convert X into a Z-score). Show work.
The amounts of sugar in a serving of children's breakfast cereals is normally distributed with a mean of 8.4 grams and a standard deviation of 2.1 grams. For a sample of 15 children's breakfast cereals, what is the probability that the sample mean amount of sugar in a serving for the 15 cereals will be at least than 10 grams? Show how you calculated your result here (type in what you typed on your calculator or computer, the function used on the calculator/computer with value input, etc) Calculation: ___________ Now type in your final simplified or rounded answer, if necessary round your answer to four decimal places. P(x¯<10 grams) = ___________
Assume that adults have 1Q scores that are normally distributed with a mean of 103.1 and a standard deviation of 24.4. Find the probability that a randomly selected adult has an IQ greater than 131.3. (Hint: Drawa graph.) The probability that a randomly selected adult from this group has an IQ greater than 131.3 is (Round to four decimal places as needed.)
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. 102 126 A symmetric bell-shaped curve is plotted over a horizontal scale. Two vertical lines run from the scale to the curve at labeled coordinates 102 and 126, which are both to the right of the curve’s center and peak. The area under the curve between the vertical lines is shaded. The area of the shaded region is enter your response here. (Round to four decimal places as needed.)
Assume that the mean height of men in the United States is 70 inches, with a standard deviation of 3 inches. A particular man is 80 inches tall. Find the z-score of his height. (Round to two decimal places.)
Today, the waves are crashing onto the beach every 5.1 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5.1 seconds. Round to 4 decimal places where possible. The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 1.4 seconds after the person arrives is P(x = 1.4) = The probability that the wave will crash onto the beach between 1.3 and 4.7 seconds after the person arrives is P(1.3 < x < 4.7) = The probability that it will take longer than 3.92 seconds for the wave to crash onto the beach after the person arrives is P(x > 3.92) = Suppose that the person has already been standing at the shoreline for 1.1 seconds without a wave crashing in. Find the probability that it will take between 2.4 and 3.8 seconds for the wave to crash onto the shoreline. 84% of the time a person will wait at least how long before the wave crashes in?…

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