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- H CPBA 5 CO H₂ Pd/C 1. NaBH4 2. H3O+ Br NH3 :0 OHOнtres OH CH3 HBr CH3CN (solvent) E1 H₂C16 The odor of fish is due primarily to amines, especially methylamine (CH3NH₂). Fish is often served with a wedge of lemon, which contains citric acid. The methylamine reacts with the citric acid to form an odorless product, methylammonium citrate, thereby making less-than- fresh fish more appetizing. K₁ for CH3NH₂ = 4.407 × 10-4 CH₂NH₂ (aq) + H₂O(1)⇒ CH₂NH3(aq) + OH(aq) A. B. What is the pH of a solution that is 0.7625 M in methylamine at 25.0 °C? pH = Please provider your answer below. t Check answer → A (0) Check answer What is the pH of a solution that is 7.007×104 M in methylamine? pH = Please provider your answer below. (0
- H₂N H₂N NH₂ H₂NOC HN -Ho Ho H₂NOC O Flo HN. H₂C H₂NOC OH HN O CO₂H NaOH/H₂O CF CO H H₂O+62. When corn is allowed to ferment, the fructose in the corn is converted to ethyl alcohol according to the following reaction C,H12O6(aq) →2C,H;OH(1) + 2CO2(g) (a) What volume of ethyl alcohol (d = 0.789 g/mL) is produced from one pound of fructose? (b) Gasohol can be a mixture of 10 mL ethyl alcohol and 90 mL of gasoline. How many grams of fructose are required to produce the ethyl alcohol in one gallon of gasohol? 71-1. The raw water supply for a community contains 18 mg/L total particulate matter. It is to be treated by addition of 60 mg alum (Al2(SO4)3-14H;O) per liter of water treated. Essentially, all the added alum precipi- tates represented by the following reaction: Al2(SO4)3 · 14H20 → 2 Al(OH);(s) + 3So,- + 6H* + 8H2O For a total flow of 7500 m/d, compute the daily alum requirement, the total concentration of suspended sol- ids in the water following alum addition, and the daily load of particulate solids requiring disposal (including both those initially present and those formed during treatment).
- 1LDA 2) 10. Br OH GMH,SO,/A NH2 11. NH2 12.You may want to reference (Page) Section 16.5 while completing this problem. Calculate (H3 o+| at 25° C for each solution and determine whether the solution is acidic, basic, or neutral.A concentrated KOH (MW = 56.105 g/mol) solution is 45.0 %wt KOH and has a density of 1.45 g/mL. How many milliliters of the concentrated KOH solution must be diluted to obtain 1000.0 mL of 1.60 M KOH?
- BaCO3 - Ba2+ + CO3? reaction was given. It is known that the carbonate anion is hydrolyzed in [HCO ][OH] [co? ] CO3- + H20 = HCO; + OH Kb1 and [H2CO3][OH¯] [HCO3] HCO; + H2O = H;CO3 - OH- Kb2 = form. Since Ka1 = 1.44x10-7, Ką2 = 4.7x10-11 and KspBaco3 = 5.1x10-9, calculate the solubility of BaCO; salt at pH = 8 and 12 depending on the pH value.What is the pH of (3.21x10^-1) M C5H5NHBR? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: х10 AnswerA chemist prepares a solution of sodium hyposulfate (Na, S,03) by measuring out 75.2 umol of sodium hyposulfate into a 100. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's sodium hyposulfate solution. Be sure your answer has the correct number of significant digits. mol L ? O
