Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for xg. √ w 6 Xg is free X₂ is free xg is free xe is free 60: Find the smallest possible value for xe. The smallest possible value for x is 100 What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. OA. OB. O D. OC. x₁ is free 120 140 x2 = X₂ is free X₂ is free E X₂ X₂ is free 158 F SO 100 x₁ is free 6 yo X₂ is free

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Intersections in England are often constructed as one-way
"roundabouts," such as the one shown in the figure. Assume that
traffic must travel in the directions shown. Find the general
solution of the network flow. Find the smallest possible value for
X8-
X₁ =
X3
X4 =
X5
X is free
X₁ =
X₂ is free
X₂ =
X4 =
X5 is free
X8
is free
60 >>>
Find the smallest possible value for xg.
The smallest possible value for X is
100
B,
*24
A
X₁
120 140
%3
What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice.
A.
B.
C.
D.
x₁ is free
is free
x2 =
X₂ is free
X₂ is free
X5 =
X is free
D
*
*1
E
x5
F
-80
100
X₂
sm
X4 =
5
X is free
Transcribed Image Text:Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X8- X₁ = X3 X4 = X5 X is free X₁ = X₂ is free X₂ = X4 = X5 is free X8 is free 60 >>> Find the smallest possible value for xg. The smallest possible value for X is 100 B, *24 A X₁ 120 140 %3 What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. A. B. C. D. x₁ is free is free x2 = X₂ is free X₂ is free X5 = X is free D * *1 E x5 F -80 100 X₂ sm X4 = 5 X is free
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