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Interpret these data to identify A, and use the 18 electron rule to rationalise its structure.

Interpret these data to identify A, and use the 18 electron rule to rationalise its structure.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Q4 Manganese chloride, MnCl2, reacts with one mole equivalent of C5H5Na then of one mole equivalent of C6H5MgBr to produce, after hydrolysis, a deep red crystalline product (A). Compound A analyses as C, 66.68; H, 5.56; Mn, 27.73% and has a molecular weight of 198.13. The ¹H NMR spectrum of A shows two singlets at 3.83ppm (5H) and 4.50ppm (6H). Its 1³C NMR spectrum similarly has two signals of relative intensities 5:6. Interpret these data to identify A, and use the 18 electron rule to rationalise its structure.
Transcribed Image Text:Q4 Manganese chloride, MnCl2, reacts with one mole equivalent of C5H5Na then of one mole equivalent of C6H5MgBr to produce, after hydrolysis, a deep red crystalline product (A). Compound A analyses as C, 66.68; H, 5.56; Mn, 27.73% and has a molecular weight of 198.13. The ¹H NMR spectrum of A shows two singlets at 3.83ppm (5H) and 4.50ppm (6H). Its 1³C NMR spectrum similarly has two signals of relative intensities 5:6. Interpret these data to identify A, and use the 18 electron rule to rationalise its structure.
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