int age; cout << "Enter an age: "; cin >> age; Write a few lines of code to print "Valid" if age is greater than 0 and less than 110 or "Invalid" otherwise. This code must always print one of the messages

Q: char x='B'; cout<<x<<x-1; а. В97 O b. B90 O C. B65 Od. Ba

A: answer is

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A: Code:

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A: The logical number will depend upon the result of the condition.

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A: Actually, c++ is a powerful general purpose language. It is a high level language.

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A: This program is in c++ Please find the answer below step.

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A: The output of above code will be: 16

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A: Given:

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A: Answer the above question are as follows

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Q: 4. s = 1; do ( s++; cout 12) 468 10 O 2 148 12

A: GIVEN:

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A: The, code has given below: