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- Please explain the code below #include <cstdio> #include <math.h> using namespace std; int main ( ) { // radius const int RAD = 10; // tolerance const int TOL = 5; for(int x = -RAD; x <= RAD; x++){ for(int y = -RAD; y <= RAD; y++){ int eq = x*x + y*y - RAD * RAD; printf(abs(eq) < TOL ? "*" : " "); printf(abs(eq) < TOL ? "*" : " "); } for(int y = -RAD+4; y <= RAD; y++){ int eq = x*x + y*y - RAD * RAD; printf(abs(eq) < TOL ? "*" : " "); printf(abs(eq) < TOL ? "*" : " "); } for(int y = -RAD+4; y <= RAD; y++){ int eq = x*x + y*y - RAD * RAD; printf(abs(eq) < TOL ? "*" : " "); printf(abs(eq) < TOL ? "*" : " "); } for(int y = -RAD+4; y <= RAD; y++){ int eq = x*x + y*y - RAD * RAD; printf(abs(eq) < TOL ? "*" : " ");…#include<stdio.h> #define FAIL_VAL -99999#define SUCCESS_VAL 99999#define MAX_USER 20#define MAX_LEN 200 char emailArr[MAX_USER][MAX_LEN];char passArr[MAX_USER][MAX_LEN]; char nameArr[MAX_USER][MAX_LEN];char addressArr[MAX_USER][MAX_LEN]; int user_count=0; int signupUser(char email[], char pass[]){ char Email_id[60]; int i;//p1=0,p2=0; printf("Enter your Email_id: "); scanf("%s", &Email_id); if(Email_id[i]=='@' && Email_id[i]=='.') { printf("Your Email_id is valid"); } else { printf("Email_id invalid.Please enter a valid id."); } } int loginUser(char email[], char pass[]){ //Write your code here} int buildUserProfile(char email[], char firstName[], char lastName[], char address[]){ //Write your code here} void searchByName(char name[]){ //Write your code here} void searchByAddress(char address[]){ //Write your code here} int main(){ while(1) {…// MichiganCities.cpp - This program prints a message for invalid cities in Michigan. // Input: Interactive // Output: Error message or nothing #include <iostream> #include <string> using namespace std; int main() { // Declare variables string inCity; // name of city to look up in array const int NUM_CITIES = 10; // Initialized array of cities string citiesInMichigan[] = {"Acme", "Albion", "Detroit", "Watervliet", "Coloma", "Saginaw", "Richland", "Glenn", "Midland", "Brooklyn"}; bool foundIt = false; // Flag variable int x; // Loop control variable // Get user input cout << "Enter name of city: "; cin >> inCity; // Write your loop here // Write your test statement here to see if there is // a match. Set the flag to true if city is found. // Test to see if city was not found to determine if // "Not a city in Michigan" message should be printed.…
- #include using namespace std; void some_action_1(int); int main() { cout<#include <stdio.h>#include <stdlib.h> typedef struct Number_struct { int num;} Number; void Swap(Number* numPtr1, Number* numPtr2) { /* Your code goes here */} int main(void) { Number* num1 = NULL; Number* num2 = NULL; num1 = (Number*)malloc(sizeof(Number)); num2 = (Number*)malloc(sizeof(Number)); int int1; int int2; scanf("%d", &int1); scanf("%d", &int2); Thank you so much but i forgot to put this how i would fit in into this. num1->num = int1; num2->num = int2; Swap(num1, num2); printf("num1 = %d, num2 = %d\n", num1->num, num2->num); return 0;}/*Line 1:*/ doublevalues[6] = {10, 20, 30, 40, 50, 60}; /*Line 2:*/ double* yalptr= values; /*Line 3:*/ cout << 3*values[1] + yalptr[3] + *(valptr + 2); A. What is 3*values[1] equal to in Line 3? (Explain) B. What is yalptr[3] equal to in Line 3? (Explain)#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…Write a function getNeighbors which will accept an integer array, size of the array and an index as parameters. This function will return a new array of size 2 which stores the neighbors of the value at index in the original array. If this function would result in returning garbage values the new array should be set to values {0,0} instead of values from the array.K Lold T T=T+(K-2)*L T=T- 10 T=0 T=T-10 K= 4, 8, 2 L=4, 3, -1 T=T+{K-2)*L#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…The following code will display 150: { int a[] = { 10,20,30,40,50 }; int sum = 0; for (int i = 0; i <= 4;i++ ) sum += a[--i]; cout << sum; Select one: True Falsezain IQ لا توجد خدمة docs.google.com Q #includeusing namespace std; int main (){ int a[100]; int i, n „large ;cout>a[i]; }large =a[0];for (i=O ; i<=99 ; i++)if (larg < a[i])larg = ali] ;cout<<" largest value in the array = "<< larg ;return 0;} true False The general form of (One- Dimensional Arrays) is:Type Array Name [number of elements] * True False Char a[5][6]; *SEE MORE QUESTIONS
