insurance. Cost item Diesel option (A) PV option (B) Capital cost $ 12000 50000 Operating & maintenance cost S/year 10000 1000 Salvage value $ 2000 1000 Evaluate the two options using, Annual cost basis. а. b. Life cycle cost basis. с. Return on investment.

insurance. Cost item Diesel option (A) PV option (B) Capital cost $ 12000 50000 Operating & maintenance cost S/year 10000 1000 Salvage value $ 2000 1000 Evaluate the two options using, Annual cost basis. а. b. Life cycle cost basis. с. Return on investment.

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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A cost analysis is to be made to determine what, if anything, should be done in a situation offering three alternatives in addition to doing nothing. Costs and benefits of the alternatives are estimated as follows: Alternative Cost Uniform Annual Benefit Residual Value Useful life (years) A 450,000 150,000 0 4 B 550,000 125,000 300,000 4 с 800,000 135,000 250,000 8 Use an 8-year analysis period, "stacking" projects as necessary. Use Excel to choose which, if any, of the projects should be chosen: MÁRR is 15%. a. Using annual worth analysis b. Using rate of return analysis
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In comparing the machines on a present worth basis, the present worth of machine X, the cost of money is 10% per year, is closest to Machine X Machine Y Initial cost, $ -66,000 -46,000 Annual cost, $/year Salvage value, $ Life, years -10,000 -15,000 10,000 24,000 3. $-103,908 $-87,840 None of the answers S-65,270
Graph on right, shows AW of costs versus number of service years of project X. Based on the graph, economic service life of the project is Larger costs Total AW of costs AW of AOC Capital recovery 3.5 10 Years О 3.5 years O 10 years O 1 year О З уears AW of costs, S/year
For the cash flows shown, determine the incremental cash flow between machines B and A for (a) year 0, (b) in year 3, and (c) in year 6. Machine First Cost, $ АОС, $/year Salvage value, $ 3,000 Life, years B -15,000 -25,000 -1,600 -400 6,000 3 4 O (a) = -10000 (b) = -1800 (c) = 1200 %3D !3! O (a) = -10000 (b) = 13200 (c) = 4200 !3! %3! O (a) = -10000 (b) = 13200 (c) =6000 %3! %3D O (a) = -10000 (b) = 13200 (c) = 13200 %3D
QUESTION 3 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% Machine A Machine B Machine C First cost, $ 15,828 30000 10000 Annual cost, $/year Salvage value, s Life, years 8,753 6,000 4,000 4,000 5,000 1,000 Answer the below questions: A- AW for machine A= QUESTION 4 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% Machine A Machine B Machine C First cost, $ 15000 21,344 10000 Annual cost, $/year 8,314 6,000 4,000 Salvage value, $ Life, years 4,000 5,000 1,000 Answer the below questions: B- AW for machine B=
Required information PEMEX, Mexico's petroleum corporation, has an estimated budget for oil and gas exploration that includes equipment for three offshore platforms as shown. Use PW analysis to select the best alternative at a MARR of 16% per year. Platform First cost, $ million Y Z -300 -450 -510 M&O, $ million per year -320 -290 -230 Salvage value, $ million 75 50 90 Estimated life, years 20 20 20 Select platform X, Y, or Z using tabulated factors. The present worth of platform X is $- 2298.4 worth of platform Z is $- 1944.14 million, the present worth of platform Y is $- 2262.15 million, and the present million. The platform selected based on the present worth is platform Z
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PW values of a project were calculated for several values of (i). The results were plotted as shown in the figure. a. What are the values of ROR (i*) for this project? Put 100 integer number followed immediately by% 75 1- 50 25 2- 10 20 30 40 50 b. If this project is a public sector project (i.e. its ROR is low). What value should we choose as the ROR for the 50 project? Put integer number followed immediately 75 by% 100 (O00TS x) Md
What Term goes with what Concept
SUBJECT: Engineering Economics Number 3