Instructions: In the parallel RLC circuit shown below, the initial voltage stored in thecapacitor is Vo = 160 V and the inductor initial current is I = -0.7 A. Answer thefollowing questions:(a) The value of a and wo(b) The form of the response of the circuit (underdamped, critically damped,overdamped)(c) The expression for ve(t) for t > 0S3200tg10 1115.625 F1 (1)Vo=160 VPRACTICE

Answered: Image /qna-images/answer/df8214ba-2cfe-4f7f-930b-d2a4adbfc438.jpg

Answered: Instructions: In the parallel RLC…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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The resistance, inductance and capacitance in a parallel RLC circuit are 1500 ohms, 400mH and 10nF, respectively a. Calculate the roots of the characteristic equation that describe the voltage response of the circuit b. Will the response be over, under or critically damped? c. What value of C will yield a damped frequency of 15 krad/s? d. What are the roots of the characteristic equation for the value of C found in (c)? e. What value of C will result in a critically damped response?
If in a circuit, E=9v and the current I reaches half its maximum value of 2A at t=0.1s after the switch is closed. What is the time constant of the circuit? What is the emf across the inductor at t=0.1s?
For an RL circuit in Transient analysis, the current on the inductor follows: Iz (t) = K₁ + K₂ e 4 R To solve for IT (t), we need to know three parameters, i.e., K₁, K2, T. By observing the above expression, we find out that: IL (0)= K₁ + K2, IL (+00) = K₁. Now, we need to find values of IL (0), IL (+∞). In the following circuit, the switch is turned from A to B at t=0. VA 10V 44 A T B R 100 m VR(t)- Similar to RC transient analysis, let draw a time axis. Switch is at A v₁(t) Switch is at B t = 0 t = 0+ immt L 10H
An LC circuit like that in the figure below consists of a 3.30-H inductor and an 836-pF capacitor that initially carries a 118-μC charge. The switch is open for t < 0 and is then thrown closed at t = 0. Compute the following quantities at t = 5.00 ms. 2max 000 (a) the energy stored in the capacitor (b) the total energy in the circuit (c) the energy stored in the inductor 0
Can you help me solve this? For two capacitors C1, C2 in series, with initial voltages (at t = 0-) V01 and V02, respectively, derive the instantaneous voltages v1(t) across C1 and v2(t) across C2 for t ≥ 0+in terms of C1, C2, V01, and V02.
My teacher said that the equation v(t) for Vcap (in image) will be V = -1/C integral of i(t) + v(initial). My question is, my teacher has said that the '-' infront of the 1/C is because the current flows into the negative terminal of the capacitor. But in the answer my teacher has put v(initial) as +20 and not -20, even though the 20V across the capacitor is also negative to positive as shown in the image. So why is the v(initial) put as +20 and not -20? Thank you.
During the transient analysis of an RL circuit, if the current through an inductor is 1.5 A at t = 0, the current through that inductor at t = (0.5 time-constant) will be: O A. Higher O B. The same O C. Lower O D. None of the other choices are correct O E. Can't tell the current until we know the voltage applied to the circuit
Asap please
Please complete the entire question quickly and I will leave you a like :) THANKS!
4. Assume that at the instant the 2A DC current source is applied to the circuit shown below, the initialcurrent in the 39 mH inductor is 1A, and the initial voltage on the capacitor is 50 V (positive at theupper terminal). Find the expression for iL(t) for t ≥ 0 if R equals 12.5 ohms.

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