Design an RLC network which, when placed in parallel with a 100 (2% tolerance) resistor, yields an equivalent parallel admittance Y = 28.627-31.900° mS at f= 100 Hz when measured across the 100 Q resistor. Use 10% tolerance (E12 standard component) value The network can have R=| 33 Q, C= |mF, and L =| 55 mH. (Round the capacitance value to one decimal place a the other two values to the nearest whole number.)
Design an RLC network which, when placed in parallel with a 100 (2% tolerance) resistor, yields an equivalent parallel admittance Y = 28.627-31.900° mS at f= 100 Hz when measured across the 100 Q resistor. Use 10% tolerance (E12 standard component) value The network can have R=| 33 Q, C= |mF, and L =| 55 mH. (Round the capacitance value to one decimal place a the other two values to the nearest whole number.)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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I'm working on a circuit design problem where I need to find the values for an RLC circuit that, when placed in parallel with a 100 Ohm resistor, results in an admittance of 28.627 /_ -31.900 mS at 100 Hz. I've successfully calculated the resistance (R = 33 Ohm) and inductance (L = 55 mH), which are correct, but am having trouble with the capacitance C. My attempts to calculate C using the capacitive reactance Xc consistently lead me to 0.02 mF, which isn't accepted as correct. The impedance I've calculated for the RLC network is Z_RLC = 33 + j34.9 Ohm. Could you help me verify the Xc calculation and find the correct value for C in mF?
Thank you!
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