Instructions: Assume that the distribution for the following scenario is normal. Use the standard normal table to find the probability. Round z-scores to the nearest hundredth. Do not round the probability from the table. The average daily jail population in the United States is 618,319. If the distribution is normal and the standard deviation is 50,200, find the probability that on a randomly selected day, the jail population is: Between 500,000 and 600,000 P(500, 000 < x <600, 000) = P(

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Author:Amos Gilat
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Instructions: Assume that the distribution for the following scenario is normal.
Use the standard normal table to find the probability. Round z-scores to the
nearest hundredth. Do not round the probability from the table.
The average daily jail population in the United States is 618,319. If the
distribution is normal and the standard deviation is 50,200, find the probability
that on a randomly selected day, the jail population is:
Between 500,000 and 600,000 P(500, 000 < x < 600, 000) = P(
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Transcribed Image Text:ndarc X Binomial X Tn Mastery X New Tab A scde-genius.mrooms.net/mod/quiz/attempt.php?... * Instructions: Assume that the distribution for the following scenario is normal. Use the standard normal table to find the probability. Round z-scores to the nearest hundredth. Do not round the probability from the table. The average daily jail population in the United States is 618,319. If the distribution is normal and the standard deviation is 50,200, find the probability that on a randomly selected day, the jail population is: Between 500,000 and 600,000 P(500, 000 < x < 600, 000) = P( Check Previous page Next page
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