You want to find a 92% confidence interval for the proportion of PLM students who get a student scholarship allowance from the government of the City of Manila. You found an information from the city administrator that states that around 75% of PLM students are to get the allowance. At maximum error of 5%, how many samples do you need?

You want to find a 92% confidence interval for the proportion of PLM students who get a student scholarship allowance from the government of the City of Manila. You found an information from the city administrator that states that around 75% of PLM students are to get the allowance. At maximum error of 5%, how many samples do you need?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

You recently sent out a survey to determine if the percentage of adults who use social media has changed from 62%, which was the percentage of adults who used social media five years ago. Of the 2751 people who responded to survey, 1740 stated that they currently use social media.a) Use the data from this survey to construct a 98% confidence interval estimate of the proportion of adults who use social media. Record the result below in the form of (#,#)(#,#). Round your final answer to four decimal places.b) Can you conclude that the percentage of adults who use social media has changed? Explain. Yes, because the proportion of adults who used social media five years ago is inside of the confidence interval. Yes, because the proportion of adults who used social media five years ago is not inside the confidence interval. No, because the proportion of adults who used social media five years ago is inside the confidence interval. No, because the proportion of adults who used social media…
Nearly one-half of Americans ages 25 to 29 are unmarried. How large a sample is necessary to estimate the true proportion of unmarried Americans in this age group within 2 percentage points with 95% confidence?
A recent survey showed that 42% of US employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 500 companies. Find the 99% confidence interval for the proportion of all companies likely to require higher employee contributions for health care coverage. (Round to four decimal places)
Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 22 students, she finds 5 who eat cauliflower. Obtain and interpret a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method.
You recently sent out a survey to determine if the percentage of adults who use social media has changed from 62%, which was the percentage of adults who used social media five years ago. Of the 2283 people who responded to survey, 1635 stated that they currently use social media.a) Use the data from this survey to construct a 94% confidence interval estimate of the proportion of adults who use social media. Record the result below in the form of (#,#)(#,#). Round your final answer to four decimal places.
One year’s survey results, of 1525 respondents, 846 said that they expected difficulty finding a job. Find a 95% confidence interval for the population proportion of students who expect difficulty finding a job.
Construct a 96% confidence interval if x=75 and n=200. Round your answers to 3 decimal places.
Wildlife biologists inspect 200 deer taken by hunters and find 45 of them carrying Lyme disease ticks. What would be the margin of error for this study with a 90% confidence interval?
You want to get a 90% confidence interval for the difference between the percentage of females with red hair compared to males with red hair. You sample 76 females and find 34 of them have red hair. You sample 65 males and find 33 have red hair. < p1−p2 <
In a article you can read, among other things, that the relative risk of death was 0.70 (95% confidence interval: 0.58- 0.85) for the exposed group compared to the unexposed group. Interpret RR and the confidence interval in your own words.
We randomly sample 600 people in a specific town. 342 of them like cats. Based on this, construct a 95% confidence interval for the true population proportion of people in this town who like cats. Give your answers as decimals, rounded to four places.
In the United States, 1000 residents aged 15 or older were surveyed and 870 replied that they were satisfied with the water quality. The 90% confidence interval estimate of all U.S residents satisfied with their water quality is