The mean was found to be 25% and the confidence interval was (20.4%,29.6%) therefore the margin of error was +/- _____%.
Q: A survey found that 73% of a random sample of 8344 American adults approved of cloning endangering…
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Q: Suppose we know that a confidence interval is (-.735, .125). Find the sample mean and the error…
A: Ans- Given, a confidence interval is (-.735, .125). Find the sample mean and the error bound.
Q: A sample of 28 adults attending a country fair determined that the mean age was 34, given that the…
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Q: 6. to the nearest percentage point, the margin of error for this survey is?
A: Given: Lower limit = 0.74 Upper limit = 0.86 The point estimate can be calculated as: Point estimate…
Q: Express the confidence interval 27.1%±8.5%27.1%±8.5% in interval form.
A: The given confidence interval is 27.1%±8.5%.
Q: The heights of American women are normally distributed. If a random sample of American women is…
A: Point estimate: The population parameter which is estimated by using sample statistic is termed as…
Q: Suppose the daily numbers of visitors at the Grand Canyon national park are normally distributed.…
A: Solution: From the given information, the confidence interval for the population mean is (17124,…
Q: A researcher investigated whether the temperature of milk, x, can be used to predict the milk's pH…
A: In this context, it is given that The prediction interval for the pH of a glass of milk whose…
Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…
A: Given information
Q: Express the confidence interval 71.4%±4.3% in interval form.
A: Express the confidence interval 71.4%±4.3% in interval form.
Q: Q1) Find the standard error for a sample. x= 450 and n = 600 when Q2) create a as%. confidence…
A: The given values are x=450 and n=600.
Q: Suppose the mean of a given data set is 651.2 with a margin of error of 97.1. Write a confidence…
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Q: In 2011 the U.S. Department of Transportation reported with 95% confidence that the average length…
A: The average length of the trip in the United States was 9.72 miles with margin of error as 0.22…
Q: Express the confidence interval 27.3%±8.3%27.3%±8.3% in interval form.
A: Given that, Confidence Interval = 27.3% ± 8.3%
Q: In the estimation of the population mean, what if given that last year mean is 7.05 and SD is…
A: Confidence Interval provides a range of values for the estimated parameter.
Q: If a 90% confidence interval for the mean is (75.3 to 80.9), we would reject H0: =70 in favor of…
A: Given, 90% confidence interval (75.3,80.9) i.e. The hypothesis to be tested is given as:
Q: The sample correlation is -0.8. If the sample size was 40, then the 99% confidence interval states…
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Q: A teacher gives a test to his class of 25 students. Since he wants to quickly obtain an estimate of…
A: The class of 25 students is considered as the population. Sample size n =12 Sample mean x¯=82 Sample…
Q: Describe about the Confidence Interval for μD.
A: Correlated samples t test or paired t test or repeated measures t test: The paired t is used when…
Q: A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol…
A: Mean difference (M) = 15.91 mg/dL Standard deviation of the mean difference (s) = 15.2714 mg/dL…
Q: Express the confidence interval 83.2%±7.2%83.2%±7.2% in interval form.
A: It is given that, The confidence interval is 83.2% ± 7.2%. We have to write the given confidence…
Q: Nearly one-half of Americans ages 25 to 29 are unmarried. How large a sample is necessary to…
A: The provided information is The margin of error is E=0.02 α=0.05 The critical value is zc=1.96…
Q: In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true…
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Q: am computed a 95% confidence interval for mean from a specific random sample. His confidence…
A: By the definition of confidence interval, it is a range of values which might or might not contain…
Q: A random sample of 49 Europeans was asked how many days of vacation they take each year. The sample…
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Q: Alfredo wants a 85% confidence interval for the true average gas mileage for a Gremlin after…
A: We have given that Sample size n =9 Sample mean =24 Population standard deviation =4 85% confidence…
Q: Write down the confidence interval formula for image 1 . Is the correct answer image 2?
A: Confidence interval: If Xi’s are n random sample from normal population with mean µX and standard…
Q: For a 95% confidence interval and n=21 give the Chi-squared right value.
A: From the provided information, Sample size (n) = 21 Confidence level = 95% The level of significance…
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- Express the confidence interval 10.8%±5.1%10.8%±5.1% in interval form.In 2011 the U.S. Department of Transportation reported with 95% confidence that the average length of a motor vehicle trip in the United States was 9.72 miles with a margin or error of 0.22 miles. With 95% confidence the authors of the report are claiming that the true average length of a motor vehicle trip in the United States is between and miles. The level of confidence for this estimate is %.A researcher investigated whether the temperature of milk, x, can be used to predict the milk's pH content, y. She predicted the pH level of a glass of milk with a temperature of 8.45 degrees to be ŷ= 6.795 a)A 95% confidence interval for the mean pH of all milk with temperature 8.45 degrees is calculated to be (6.76, 6.83). Which of the following is the correct interpretation of this confidence interval? -The mean pH level for all glasses of milk having a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -The pH level for one glass of milk with a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -There is a probability of 0.95 that the mean pH level for this glass of milk with temperature 8.45 degrees is between 6.76 and 6.83. -95% of all glasses of milk with a temperature of 8.45 degrees have a pH level between 6.76 and 6.83. b)Suppose we have a glass of milk whose temperature is 8.45 degrees. We…
- Solve Question 2 Please show workExpress the confidence interval 80.1%±3.4%80.1%±3.4% in interval form.In a sample of 300 adults, 198 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places RectanRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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