× Incorrect The horizontal top of a concrete column is subjected to the system of forces shown. Represent the resultant of all forces as a force R at point O and a couple M. Also specify the magnitudes of R and M. 6 KN 0.6 m 5 kN 0.8 m 3 KN 0.8 m 2 kN 0.4 m 5 kN 1 kN 7 kN 3 KN Answers: R = ( i 4 M = ( i -5.4 0.4 m 0.4 m i i 7 j i 15 k) KN i+ i 4 j+ i -2.4 k) kN·m R = i 17.03 KN M = i 7.13 kN·m
× Incorrect The horizontal top of a concrete column is subjected to the system of forces shown. Represent the resultant of all forces as a force R at point O and a couple M. Also specify the magnitudes of R and M. 6 KN 0.6 m 5 kN 0.8 m 3 KN 0.8 m 2 kN 0.4 m 5 kN 1 kN 7 kN 3 KN Answers: R = ( i 4 M = ( i -5.4 0.4 m 0.4 m i i 7 j i 15 k) KN i+ i 4 j+ i -2.4 k) kN·m R = i 17.03 KN M = i 7.13 kN·m
Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN:9781305081550
Author:Braja M. Das
Publisher:Braja M. Das
Chapter6: Vertical Stress Increase In Soil
Section: Chapter Questions
Problem 6.4P: Refer to Figure P6.4. A strip load of q = 900 lb/ft2 is applied over a width B = 36 ft. Determine...
Related questions
Question
7.
![× Incorrect
The horizontal top of a concrete column is subjected to the system of forces shown. Represent the resultant of all forces as a force R at
point O and a couple M. Also specify the magnitudes of R and M.
6 KN
0.6 m
5 kN 0.8 m
3 KN
0.8 m 2 kN
0.4 m
5 kN
1 kN
7 kN
3 KN
Answers:
R = ( i
4
M = ( i
-5.4
0.4 m
0.4 m
i
i
7
j
i
15
k) KN
i+
i
4
j+
i
-2.4
k) kN·m
R = i 17.03
KN
M = i
7.13
kN·m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc59a6d07-a993-40f7-b57e-cdb2ad079d78%2Fec031c2d-bed2-4ec9-ba12-5961dfbf19c0%2F7zxly4_processed.png&w=3840&q=75)
Transcribed Image Text:× Incorrect
The horizontal top of a concrete column is subjected to the system of forces shown. Represent the resultant of all forces as a force R at
point O and a couple M. Also specify the magnitudes of R and M.
6 KN
0.6 m
5 kN 0.8 m
3 KN
0.8 m 2 kN
0.4 m
5 kN
1 kN
7 kN
3 KN
Answers:
R = ( i
4
M = ( i
-5.4
0.4 m
0.4 m
i
i
7
j
i
15
k) KN
i+
i
4
j+
i
-2.4
k) kN·m
R = i 17.03
KN
M = i
7.13
kN·m
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