include using namespace std; int main() { char *ptr; char Str[ ] = "abcdefg"; ptr = S
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#include <iostream>
using namespace std;
int main()
{
char *ptr;
char Str[ ] =
"abcdefg"; ptr =
Str;
ptr += 5;
cout
<< ptr;
return
0;
}
a) fg
b) cdef
c) defg
d) abcdbcd
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- In the C programming language, if all function prototypes are listed at the top of your code, outside and above all functions, you do not need to worry about the order of the function definitions within the code. True FalseC++ Program: #include <iostream>#include <string> using namespace std; const int AIRPORT_COUNT = 12;string airports[AIRPORT_COUNT] = {"DAL","ABQ","DEN","MSY","HOU","SAT","CRP","MID","OKC","OMA","MDW","LAX"}; int main(){ // define stack (or queue ) here string origin; string dest; string citypair; cout << "Loading the CONTAINER ..." << endl; // LOAD THE STACK ( or queue) HERE // Create all the possible Airport combinations that could exist from the list provided. // i.e DALABQ, DALDEN, ...., ABQDAL, ABQDEN ... // DO NOT Load SameSame - DALDAL, ABQABQ, etc .. cout << "Getting data from the CONTAINER ..." << endl;// Retrieve data from the STACK/QUEUE here } Using the attached program (AirportCombos.cpp), create a list of strings to process and place on a STL STACK container. The provided code is meant to be generic. Using the provided 3 char airport codes, create a 6 character string that is the origin &…#include <bits/stdc++.h> using namespace std; struct Employee { string firstName; string lastName; int numOfHours; float hourlyRate; char major[2]; float amount; Employee* next; }; void printRecord(Employee* e) { cout << left << setw(10) << e->lastName << setw(10) << e->firstName << setw(12) << e->numOfHours << setw(12) << e->hourlyRate << setw(10) << e->amount << setw(9) << e->major[0]<< setw(7) << e->major[1]<<endl; } void appendNode(Employee*& head, Employee* newNode) { if (head == nullptr) { head = newNode; } else { Employee* current = head; while (current->next != nullptr) { current = current->next; } current->next = newNode; } } void displayLinkedList(Employee* head) { Employee* current = head; if(current!=nullptr){ cout…
- #ifndef INT_SET_H#define INT_SET_H #include <iostream> class IntSet{public: static const int DEFAULT_CAPACITY = 1; IntSet(int initial_capacity = DEFAULT_CAPACITY); IntSet(const IntSet& src); ~IntSet(); IntSet& operator=(const IntSet& rhs); int size() const; bool isEmpty() const; bool contains(int anInt) const; bool isSubsetOf(const IntSet& otherIntSet) const; void DumpData(std::ostream& out) const; IntSet unionWith(const IntSet& otherIntSet) const; IntSet intersect(const IntSet& otherIntSet) const; IntSet subtract(const IntSet& otherIntSet) const; void reset(); bool add(int anInt); bool remove(int anInt); private: int* data; int capacity; int used; void resize(int new_capacity);}; bool operator==(const IntSet& is1, const IntSet& is2); #endifint cal_media() {cout<<"Enter Your Name"<<endl;cin>>name;cout<<"Enter the Both subject marks"<<endl;cin>>marks1>>marks2;totalmarks = marks1 + marks2;} Question 4: On above code overload unary operator prefix decrement and post fix increment forthe calc-media() function.#include <iostream> #include <string> #include "complex.h" using namespace std; int main(){ // Construct 2 complex numbers Complex test1 = Complex(1,2); Complex test2 = Complex(3,4); cout << "test1: "; test1.print(); cout << endl; cout << "test2: "; test2.print(); cout << endl; Complex addition = test1.add(test2); cout <<"Add: "; addition.print(); cout << endl; Complex multiplication = test1.multiply(test2); cout <<"Multiply: "; multiplication.print(); cout << endl; Complex division = test1.divide(test2); cout <<"Divide: "; division.print(); cout << endl; Complex conjugate_value = test1.conjugate(); cout <<"Complex conjugate: "; conjugate_value.print(); cout << endl; return 0; }
- #include <iostream>//#include <vector> using namespace std; class Vec {public:Vec() {sz = 0;cap = 1;p_arr = new int[cap];} int size(){return this->sz;}int capacity(){return this->cap;}void reserve( int n ){// TODO:// (0) check the n should be > size, otherwise// ignore this action.if ( n > sz ){// (1) create a new int array which size is n// and get its address//cout << "Adress:"<< &n << endl;int *newarr = new int [n];//cout << "Address: " << newarr << endl; // location // (2) use for loop to copy the old array to the// new arrayfor(int i = 0; i < sz; i++){newarr[i] = p_arr[i];}// (3) update the variable to the new addressthis->cap=n; // (4) delete old arraydelete[] newarr;}}void push_back( int v ){// TODO:if ( sz == cap ){ cap *= 2; reserve(cap);}p_arr[sz++] = v;// complete others}int at(int idx){return this->p_arr[idx];}private://vector<int> arr;int *p_arr;int sz = 0;int cap = 0; }; int main(){Vec v;…#include <iostream> #include <string> #include <cstdlib> using namespace std; template<class T> class A { public: T func(T a, T b){ return a/b; } }; int main(int argc, char const *argv[]) { A <float>a1; cout<<a1.func(3,2)<<endl; cout<<a1.func(3.0,2.0)<<endl; return 0; } Give output for this code.5. Memory Layout Given the C struct definition below struct Simplestruct { int i; char c; double d; unsigned char a[11]; float f; }; struct Simplestruct ssp; Assume that int's are 4 bytes and have 4 byte alignment and that double has 8 byte alignment and float has 4 byte alignment. if calling printf("$x\n",ssp) yields CA028, what is the address of each field? You should express the answers in hexadecimal. &ssp->i = &ssp->c = &ssp->d = &ssp->a = &ssp->f =
- #include <conio.h>#include <iostream>#include <string> using namespace std;bool check = true;struct node {char name[20];char jobtitle[20];int empno;char branch;node *next;}*head,*lastptr; // pointes void add() // calling {node *p; //*p pomiterp=new node;cout<<"Enter name of employ:"<<endl;gets(p->name);cout<<"Enter job title of employ:"<<endl;gets(p->jobtitle);cout<<"Enter Number of employ:"<<endl;cin>>p->empno;cout<<"Enter branch of employ:"<<endl;cin>>p->branch;p->next=NULL; if(check) //if check is true its means heads is empty and there is no node exist.{head = p;lastptr = p;check = false;}else{lastptr->next=p;lastptr=p;}cout<<endl<<"Recored Entered";} void modify() {node *ptr; node *prev=NULL;node *current=NULL;int e_no;cout<<"Enter Number to…2. int count(1); while(count <5) { } --count; std::cout << count << endl; Maal#include #include #include #define SIZE 5 int nums [SIZE] = [5,0,6,1,2); int main() { int i; pid_t pid; pid= fork(); if (pid == 0) { for (i = 0; i 0) { wait (NULL); } for (i = 0; i < SIZE; i++) printf("PARENT: %d\n", nums [i] + 1); /* LINE Y */ return 0; From the above-given program, please state what will be the output at lines X and Y. Explanation in detail required for output at both lines X and Y.
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