#include main(){int a, b, c,d;clrscr();printf("enter the two variables a,b");scanf("%d %d",&a,&b);printf("enter the option 1: Addition,2:subtraction, 3: multiplication, 4: division");scanf("%d", &c);switch(c){case 1:da+b;printf("Addition of two no.=%d", d);break;case 2:d = a-b;printf("Subtraction of two no.=%d", d);break;case 3:d = a*b;printf("Multiplication of two no.=%d", d);break;case 4:d = a/b;printf("division of two no.-%d",d);break;}}(a) Draw the DD graph for the program.(b) Calculate the cyclomatic complexity of the program using all four methods.(c) List all independent paths.(d) Design all test cases from independent paths.(e) Derive all du-paths and dc-paths using data flow testing.

To answer the questions about the provided C program, we need to analyze its structure and logic.…

Answered: #include main() { int a, b, c,d;…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include<stdio.h> #include<conio.h> int mutex=1,full=0,empty=1,x=0; main() { int n; void producer(); void consumer(); int wait(int); int(signal); printf("\n1. Producer \n2. Consumer \n,3. Exit \n"); while(1) { printf("\n Enter the choice:"); scanf("%d", &n); switch(n); { case-1: if((mutex==1)&&(empty!=0)) producer(); else printf("Nuffer is full"); break; case-2: if((mutex==1)&&(full!=0)) consumer(); else print("Buffer is empty"); break; case-3: exit(0); break; } } } int wait(int s) {return(--s); } int signal(int s) { return(++s); } void producer() { mutex = wait(mutex); full = signal(full); empty=wait(empty); x++; printf("\n Producer produces the item %d",x); mutex= signal(mutex); } void consume() { mutex = wait(mutex); full = wait(full); empty = signal(empty); printf("\n Consumer consumes item %d",x); x--; mutex = signal(mutex); } CONVERT THIS C LANGUAGE CODE IN BASH SCRIPT THANKYOU
Given C code: #include <stdio.h>typedef struct compound { float realNumber; float imaginaryNumber;} compound; compound add(compound n1, compound n2); int main() { compound n1, n2, temp; printf("For the first compound number \n"); printf("Enter the real and imaginary parts: "); scanf("%f %f", &n1.realNumber, &n1.imaginaryNumber); printf("\nFor the second compound number \n"); printf("Enter the real and imaginary parts: "); scanf("%f %f", &n2.realNumber, &n2.imaginaryNumber); temp = add(n1, n2); printf("Sum = %.1f + %.1fi", temp.realNumber, temp.imaginaryNumber); return 0;} compound add(compound n1, compound n2) { compound temp; temp.realNumber = n1.realNumber + n2.realNumber; temp.imaginaryNumber = n1.imaginaryNumber + n2.imaginaryNumber; return (temp);} Task: Please change the C program above to execute complicated numeral multiplication. Hint: (e+fi)(g+hi) = (eg−fh) + (eh+fg)i
Create the following c functions:- void acceptSubscribers(Subscriber *, int size); // accept all subscriber inputs- void displaySubscribers(Subscriber *, int size); // display all subscribers- void displaySubscriber(Subscriber); // display 1 subscriber- Subscriber * getSubscribersWithPlan(Subscriber *, int size, char *); // get subscribers with desired plan
1) Find the errors in the following codes: int main() { int { Hanging Indent #include ; int a = 1;b = 4; c, d C + = a++; d = 5--; printf("Please enter an inter: "); scanf("%f", num) d = (num = 0? a+b:a+b+c); sum = (a:b:c:d: a+b+c+d); printf("Sum is %d: \n", Sum); Return 0; } 2) Assume a, b, c and n are float variables, and d, e, fand m are integer variables, what is the result of each “printf” function in the following program? Please do not run IDE to get the results.
Write a program in C++ code:
English (e what is the output of the following program? #include int test (int &, int); main () { int a=10, b=15; test (b, a); test (a,b); cout<
#include<stdio.h> #include<math.h> int main() { char cod; int gal; float cost; printf("Data Codes:"); printf(" \n H-Home \n C-Commercial \n I-Industrial "); printf("\nInput data code: "); scanf("%c", &cod); printf("\nInput number of water (in gallons) used: "); scanf("%d", &gal); if (cod=='H'|| cod=='h') { cost = 250+(0.002*gal); printf("\nTOTAL COST IS %.2f", cost); } else if (cod=='C'||cod=='c') { if (gal<=4000000) { printf("\nTOTAL COST IS 5000.00"); }…
// SumAndProduct.cpp - This program computes sums and products // Input: Interactive// Output: Computed sum and product #include <iostream>#include <string>void sums(int);void products(int);using namespace std; int main() { int number; cout << "Enter a positive integer or 0 to quit: "; cin >> number; while(number != 0) { // Call sums function here // Call products function here cout << "Enter a positive integer or 0 to quit: "; cin >> number; } return 0;} // End of main function// Write sums function here// Write products function here
#include <iostream> #include <cmath> using namespace std; // declare functions void display_menu(); void convert_temp(); double to_celsius(double fahrenheit); double to_fahrenheit(double celsius); int main() { cout << "Convert Temperatures\n\n"; display_menu(); char again = 'y'; while (again == 'y') { convert_temp(); cout << "Convert another temperature? (y/n): "; cin >> again; cout << endl; } cout << "Bye!\n"; } // define functions void display_menu() { cout << "MENU\n" << "1. Fahrenheit to Celsius\n" << "2. Celsius to Fahrenheit\n\n"; } void convert_temp() { int option; cout << "Enter a menu option: "; cin >> option; double f = 0.0; double c = 0.0; switch (option) { case 1: cout << "Enter degrees Fahrenheit: "; cin >> f; c =…
PROGRAMMING LANGUAGE: c++
#include <stdio.h>#include <stdlib.h>#include <unistd.h>#include <sys/types.h>#include <sys/wait.h> int main(){ int i, s; int a[] = {23,4,8,33,25,7,12,6,49,50,11,20,21,24,35}; pid_t pid; pid = fork(); if (pid == 0) { printf("I'm a child, I'll be printing the even numbers:\n"); for(i=0;i<(sizeof(a)/sizeof(int));i++) if(a[i]%2 == 0) printf("%d ",a[i]); } else { printf("I'm the parent, I'll be printing the odd numbers:\n"); if (pid > 0) pid = waitpid(pid, &s, 0); for(i=0;i<(sizeof(a)/sizeof(int));i++) if(a[i]%2 != 0) printf("%d ",a[i]); } return 0;} the output seem to have some error whereby it cannot output the number for the first if
#include <stdio.h>int main (){ unsigned int x = 0x76543210; char *c = (char*) &x; printf ("*c is: 0x%x\n", *c); if (*c == 0x10) { printf ("Architecture is little endian. \n"); } else { printf ("Architecture is big endian. \n"); } return 0;} void printBin(int n){ unsigned i; for (i = 1 << 31; i > 0; i = i / 2) (n & i) ? printf("1") : printf("0");} int main(void){ printBin(17); printf("\n"); printBin(4);}

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