#include int mystery3( const char 's1, const char 's2 ); int main() char string1[ 80 J;: char string2[ 80 ]: printf( "Enter two strings: " ); scanf( "%s%s", string1, string2 );: printf( "The result is %din", mystery3( string1, string2 ) ); return 0; int mystery3( const char "s1, const char 's2) for (: "s1 != 10 && "s2 != \0"; s1++, s2++) { if ( "s1 1= "s2 ) { return 0:
#include int mystery3( const char 's1, const char 's2 ); int main() char string1[ 80 J;: char string2[ 80 ]: printf( "Enter two strings: " ); scanf( "%s%s", string1, string2 );: printf( "The result is %din", mystery3( string1, string2 ) ); return 0; int mystery3( const char "s1, const char 's2) for (: "s1 != 10 && "s2 != \0"; s1++, s2++) { if ( "s1 1= "s2 ) { return 0:
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
![Question 6: Determine what does this program perform?
#include <stdio.h>
int mystery3( const char "s1, const char *s2 );
int main()
{
char string 1[ 80 ];
char string2[ 80 ]):
printf( "Enter two strings: " );
scanf( "%s%s", string1, string2 );
printf( "The result is %d\n", mystery3( string1, string2 ) );
return 0;
int mystery3( const char *s1, const char "s2 )
{
for (; "s1 != \0' && "s2 != \0°; s1++, s2++ ) {
if ( "s1 != "s2 ) {
return 0;
return 1;
Answer:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb880b9eb-af08-4eb5-b209-4a467aa0ea79%2F7c634cf1-b2a5-470e-8aa1-b6bcf31b33d7%2Fnbwlf99_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 6: Determine what does this program perform?
#include <stdio.h>
int mystery3( const char "s1, const char *s2 );
int main()
{
char string 1[ 80 ];
char string2[ 80 ]):
printf( "Enter two strings: " );
scanf( "%s%s", string1, string2 );
printf( "The result is %d\n", mystery3( string1, string2 ) );
return 0;
int mystery3( const char *s1, const char "s2 )
{
for (; "s1 != \0' && "s2 != \0°; s1++, s2++ ) {
if ( "s1 != "s2 ) {
return 0;
return 1;
Answer:
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