17. Given the following C code, what is the value of scores[5]? int scores[] = {95,82,71,90,69,67,100,54);
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![17. Given the following C code, what is the value of scores[5]?
int scores[] = {95,82,71,90,69,67,100,54);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F82aefee1-a4fd-40e7-8b3f-97f92bfc6e2a%2F48cb8586-5bd2-40e3-9cb3-ba358d98fab4%2Fkluudai_processed.png&w=3840&q=75)
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- #include <stdio.h> struct Single { int num; }; void printSingle(int f) { int binaryNum[33]; int i = 0; while(f>0) { binaryNum[i] = f % 2; f = f/2; i++; } for (int j=i-1; j>= 0; j--) { printf("%d",binaryNum[j]); } } int main() { struct Single single; single.num = 33; printf("Number: %d\n",single.num); printSingle(single.num); return 0; }#include <stdio.h> struct Single { int num; }; void printSingle(int f) { int binaryNum[33]; int i = 0; while(f>0) { binaryNum[i] = f % 2; f = f/2; i++; } for (int j=i-1; j>= 0; j--) { printf("%d",binaryNum[j]); } } int main() { struct Single single; single.num = 33; printf("Number: %d\n",single.num); printSingle(single.num); return 0; }Q1 #include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…
- Write a statement that assigns the value 50 to the very last element in the values array int[,] values = new decimal[200, 100];What occurs when using the ref or out keyword with an array parameter?In c++, Declare a constant “ SIZE = 5 ” Declare an array of ints , of size SIZE . Initializethat array to have the values 10, 12, 15, 19, 6 .– Write a loop that calculates and prints out the minimum value of the array.– Write a loop that calculates and prints out the maximum value of the array.– Write a loop that calculates and prints out the average value of the array.
- Summary In this lab, you use what you have learned about searching an array to find an exact match to complete a partially prewritten C++ program. The program uses an array that contains valid names for 10 cities in Michigan. You ask the user to enter a city name; your program then searches the array for that city name. If it is not found, the program should print a message that informs the user the city name is not found in the list of valid cities in Michigan. The file provided for this lab includes the input statements and the necessary variable declarations. You need to use a loop to examine all the items in the array and test for a match. You also need to set a flag if there is a match and then test the flag variable to determine if you should print the the Not a city in Michigan. message. Comments in the code tell you where to write your statements. You can use the previous Mail Order program as a guide. Instructions Ensure the provided code file named MichiganCities.cpp is…#include using namespace std; void scanPrice (string [], double []); // Do not modify the code double printReceipt(string [], double[]); // Do not modify the code int main () { double sum; string item [3] = {"Vegetable","Egg", "Meat"}; double price [3];| %3D scanPrice (item,price); sum = RrintReceipt (item,price); cout Price: 10 The price of Vegetable is RM 2 The price of Egg is RM 3 The price of Meat is RM 10 Your total expenses is RM 15#include <stdio.h> struct Single { int num; }; void printSingle(int f) { int binaryNum[33]; int i = 0; while(f>0) { binaryNum[i] = f % 2; f = f/2; i++; } for (int j=i-1; j>= 0; j--) { printf("%d",binaryNum[j]); } } int main() { struct Single single; single.num = 33; printf("Number: %d\n",single.num); printSingle(single.num); return 0; }
- Problem Description - JAVA PROGRAMMING Use a Two-dimensional (3x3) array to solve the following problem: Write an application that inputs nine numbers, each of which is between 1 and 10, inclusive. Display the array after the user inputs each value. Rotate/flip the array by changing places. Make the rows columns and vice versa. You have to move the elements to their new locations. Remember to validate the input and display an error message if the user inputs invalid data. Documentation and the screenshot(s) of the results. Example: 1 2 3 4 5 6 7 8 9 the result will be : 1 4 7 2 5 8 3 6 9#include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…In C++