#include double f(double x) { return 4 * exp(-x); } double trapezoidalRule(double a, double b, int N) { double h = (b - a) / N; double sum = 0.5 * (f(a) + f(b)); for (int i = 1; i < N; i++) { sum += f(a + i * h); } return h * sum; } int main() { double a = 0.0; // lower limit double b = 1.0; // upper limit int N = 5; // number of trapezoids double integral = trapezoidalRule(a, b, N); std::cout << "The estimate of the integral of f(x) = 4e^-x between " << a << " and " << b << " using " << N << " trapezoids is: " << integral << std::endl; return 0; } Please write down the explanation, step by step for this trapezoidal rule program, Emphasize on this part:for (int i = 1; i < N; i++) { sum += f(a + i * h); }
#include double f(double x) { return 4 * exp(-x); } double trapezoidalRule(double a, double b, int N) { double h = (b - a) / N; double sum = 0.5 * (f(a) + f(b)); for (int i = 1; i < N; i++) { sum += f(a + i * h); } return h * sum; } int main() { double a = 0.0; // lower limit double b = 1.0; // upper limit int N = 5; // number of trapezoids double integral = trapezoidalRule(a, b, N); std::cout << "The estimate of the integral of f(x) = 4e^-x between " << a << " and " << b << " using " << N << " trapezoids is: " << integral << std::endl; return 0; } Please write down the explanation, step by step for this trapezoidal rule program, Emphasize on this part:for (int i = 1; i < N; i++) { sum += f(a + i * h); }
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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#include
double f(double x) {
return 4 * exp(-x);
}
double trapezoidalRule(double a, double b, int N) {
double h = (b - a) / N;
double sum = 0.5 * (f(a) + f(b));
for (int i = 1; i < N; i++) {
sum += f(a + i * h);
}
return h * sum;
}
int main() {
double a = 0.0; // lower limit
double b = 1.0; // upper limit
int N = 5; // number of trapezoids
double integral = trapezoidalRule(a, b, N);
std::cout << "The estimate of the integral of f(x) = 4e^-x between " << a << " and " << b << " using " << N << " trapezoids is: " << integral << std::endl;
return 0;
}
Please write down the explanation, step by step for this trapezoidal rule program,
Emphasize on this part:for (int i = 1; i < N; i++) {
sum += f(a + i * h);
}
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