**Text Explanation:**In wild sunflowers, populations occur that are either yellow flowers (wild type) or white flowers. One variety of true breeding white-flowered plants was crossed to another pure strain of white-flowered plant. The resulting F1 progeny were yellow-flowered plants. When the F1 progeny were intercrossed, the offspring were 56 yellow-flowered and 44 white-flowered. From the results of these crosses, how many genes control the flower color? Is any one gene epistatic to any other gene?**Diagram Explanation:**The diagram consists of a flow chart showing the progression and transformation of flower color:- "white" is written at the start of an arrow.- The arrow points to "creaton".- Another arrow from "creaton" points to "red".This suggests a process of phenotypic transformation or a genetic pathway influencing color change.

Name: **Text Explanation:**In wild sunflowers, populations occur that are e
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: **Text Explanation:**In wild sunflowers, populations occur that are either yellow flowers (wild type) or white flowers. One variety of true breeding white-flowered plants was crossed to another pure strain of white-flowered plant. The resulting F1 p

A trait is a characteristic feature that is unique to specific individual. Each trait is represented by genotype and phenotype. Genotype is indicated by specific alleles . As per the question , there are two types of flower colour in sunflower :- I ) White flower II ) Yellow flower Two white flower ar crossed with each other , F1 obtained will be yellow. So , Genotype of Parent 1 = YYww Gametes produced by parent 1 = Yw Genotype of Parent 2 = yyWW Gametes produced by Parent 2 = yW When both parents are crossed with each other , genotype of F1 will be YyWw and phenotype will be yellow. Now , F1 ( YyWw) are self crossed with each other. Gametes produced by F1 will be YW , Yw , yW and yw . Cross will be as follows:- Gametes YW Yw yW yw YW YYWW (yellow) YYWw (yellow) YyWW (yellow) YyWw (yellow) Yw YYWw (yellow) YYww (white) YyWw (yellow) Yyww (white) yW YyWW (yellow) YyWw (yellow) yyWW (white) yyWw (white) yw YyWw (yellow) Yyww (white) yyWw (white) yyww (white)From the above cross , total 16 offsprings are produced. Out of which , 9 are yellow and 7 are white . Interpretation :- I ) When two Dominant genes Y and W interact with each other , then yellow colour is produced. II ) This means , two genes are involved for producing flower colour . III) Gene w/ w is epistatic to gene Y and y . While , gene y / y is epistatic to gene W and w . So , yes , one gene is epistatic to another gene. IV ) As per the question, 56 offsprings are yellow while 44 offsprings are white . 56 : 44 ratio is reduced to 9 ( yellow) : 7 ( white ) . So , this is an example of duplicate recessive epistasis.