In which direction is DNA synthesized and in which orientation relative to its template?O 3'->5'; parallel to templateO 3'->5'; antiparallel to templateO 5'->3' ; antiparallel to templateO 5'->3'; parallel to template

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Description: In which direction is DNA synthesized and in which orientation relative to its template?O 3'->5'; parallel to templateO 3'->5'; antiparallel to templateO 5'->3' ; antiparallel to templateO 5'->3'; parallel to template

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In which direction is DNA synthesized and in which orientation relative to its template? O 3'->5'; parallel to template 3'->5'; antiparallel to template O 5'->3'; antiparallel to template O 5'->3'; parallel to template

In which direction is DNA synthesized and in which orientation relative to its template? O 3'->5'; parallel to template 3'->5'; antiparallel to template O 5'->3'; antiparallel to template O 5'->3'; parallel to template

Biochemistry

6th Edition

ISBN:9781305577206

Author:Reginald H. Garrett, Charles M. Grisham

Publisher:Reginald H. Garrett, Charles M. Grisham

Chapter17: Metabolism: An Overview

Section: Chapter Questions

Problem 13P: What Art the Features of the Series of -omes? Define the following terms: a. Genome b. Transcriptome...

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What will be the newly synthesized DNA from the template given? DNA Template 3 - CGGATGCCCGTATAC-5 O 3- GCCTACGGGCATATG -5 O 5-GCCTACGGGCATAAG -3 O 5- GCCTACGGGCATATG-3 O3-CGGATGCCCGTATAC -5
At a specific area of a chromosome, the sequence of nucleotides below is present where the chain opens to form a replication fork: 3' C C T A G G C T G C A A T C C 5' An RNA primer is formed starting at the underlined T (T) of the template. Which of the following represents the primer sequence? 5' G C C T A G G 3' 5' A C G U U A G G 3' 5' A C G T T A G G 3' 5' G C C U A G G 3'
Given the following template DNA strand, what is the correct complementary DNA sequence? 3' CGC AGT GGA CAT TTC 5' O 5' GCG TCA CCT GTA AAG 3' O 5' GAA ATG TCC ACT GCG 3' O 5' GCG UCA CCU GUA AAG 3' O 5' GAA AUG UCC ACU GCG 3'
What is the DNA template of the following DNA coding: ATGGCTAACCTTGTA
In a standard procedire, when writing and reading base sequences for nucleic acids (both DNA and RNAs) always to specify base sequence in 5' > 3' direction unless otherwise directed 1. From the base sequence 5' A-T-G-C-C-A 3' in a DNA template strand, determine the base sequence in hnRNA synthesized from the DNA template strand 2. From the base sequence 5' T-A-A- C-C-T 3' in a DNA template strand, determine the base sequence in hnRNA synthesized from the DNA template strand
Lagging strand: is synthesized discontinuously in the replication fork. direction toward the N terminal to the C terminal From the nitrogenous base to the phosphate group 5-> 3' 3'-> 5 direction toward the Leading strand: is synthesized continuously in the replication fork. N terminal to the C terminal From the nitrogenous base to the phosphate group 5-> 3' O 3'-> 5' How would the DNA sequence GCTATA be transcribed to MRNA? GCUAUA CGATAT CGAUAU O GCUTUT What bases would be found on the other strand of the DNA sequence GCTATA ? GCUAUA CGATAT CGAUAU GCUTUT O O O O O OO OO
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For the following short sequence of double stranded DNA, design primers (just ~ 3-4 bases) and show 2 copy cycles of PCR (refer to figure 13.25) for the amplification of this sequence of DNA (so that you have 4 double stranded DNA). 5’- GGTATTGGCTACTTACTGGCATCG- 3’ 3’- CCATAACCGATGAATGACCGTAGC- 5’
Given the following template DNA strand, what is the correct complementary DNA sequence? 3' CGC AGT GGA CAT TTC 5'
In the diagram shown below representing a replisome, the portion represented by the letter functions to remove positive supercoils formed ahead of the replication fork. functions to load the sliding clamp onto the template DNA and the portion represented by the letter 'K H. -D 'B B; D O C; E B; F A; F O L; E
DNA is made of two strands that are antiparallel. If one strand runs from 3’ to 5’ direction the other one will go from 5’ to 3’ direction. During replication or transcription, whatever the process is, it will always follow the 5’ to 3’ direction using the 3’ to 5’ directed strand as the template strand. Therefore, if following is the DNA sequence5’-CCG ATC GCA CAA-3’a) Using this sequence as template after transcription no protein can be translated. Why? I. Presence of start codonII. Absence of start codonIII. Due to mutationb) If you want to start the translation, what change you need in the second codon (from 5’ to 3’ direction)?I. Substitution of C with GII. No changeIII. Deletion of CIV. Both I & III
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