In today's Lab we will explore a specific way to perform a Depth First Search (DFS) of a given Graph [Ref : Figure 1]. You will implement the traversal using one of the two ways stated below : [1] With Recursion. When you follow the traversal process as specified - the complexity of the solution will be linear as shown below. Time Complexity: O(V + E), where V is the number of Vertices and E is the number of Edges respectively. Space Complexity: O(V )
In today's Lab we will explore a specific way to perform a Depth First Search (DFS) of a given Graph [Ref : Figure 1]. You will implement the traversal using one of the two ways stated below : [1] With Recursion. When you follow the traversal process as specified - the complexity of the solution will be linear as shown below. Time Complexity: O(V + E), where V is the number of Vertices and E is the number of Edges respectively. Space Complexity: O(V )
Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Jav ADDCOMMENT in code, please Do TEST-CASES address your test cases in the form of code and not prose :)
In today's Lab we will explore a specific way to perform a Depth First Search
(DFS) of a given Graph [Ref : Figure 1]. You will implement the traversal using one of the two ways stated below :
[1] With Recursion.
When you follow the traversal process as specified - the complexity of the solution will be linear as shown below.
Time Complexity: O(V + E), where V is the number of Vertices and
E is the number of Edges respectively.
Space Complexity: O(V )
![[1] With Recursion.
1
[2] Iteratively by using an explicit Stack.
3
2
4
Figure 1: Graph for Traversal](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d009b7a-5e1c-499c-a434-821054b9abc8%2F6d60cca2-3f10-4d84-9787-5e11482fb33d%2Fg88r05_processed.png&w=3840&q=75)
Transcribed Image Text:[1] With Recursion.
1
[2] Iteratively by using an explicit Stack.
3
2
4
Figure 1: Graph for Traversal
![/* Class representing a directed graph using adjacency lists */
static class Graph
int V; //Number of Vertices
LinkedList<Integer>[] adj; // adjacency lists
//Constructor
Graph(int V)
this.V = V;
adj = new LinkedList (V);
for (int i = 0; i < adj.length; i++)
adj [i] = new LinkedList<Integer>();
//To add an edge to graph
2
void addEdge (int v, int w)
adj [v].add(w); // Add w to the list of v.
The edges of the Graph is given to you.
g. addEdge (0, 1);
g. addEdge (0, 2);
g. addEdge (2, 3);
g. addEdge (2, 4);
g. addEdge (4, 5);
g. addEdge (1, 3);
g. addEdge (3, 5);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d009b7a-5e1c-499c-a434-821054b9abc8%2F6d60cca2-3f10-4d84-9787-5e11482fb33d%2Fbhp8pl9_processed.png&w=3840&q=75)
Transcribed Image Text:/* Class representing a directed graph using adjacency lists */
static class Graph
int V; //Number of Vertices
LinkedList<Integer>[] adj; // adjacency lists
//Constructor
Graph(int V)
this.V = V;
adj = new LinkedList (V);
for (int i = 0; i < adj.length; i++)
adj [i] = new LinkedList<Integer>();
//To add an edge to graph
2
void addEdge (int v, int w)
adj [v].add(w); // Add w to the list of v.
The edges of the Graph is given to you.
g. addEdge (0, 1);
g. addEdge (0, 2);
g. addEdge (2, 3);
g. addEdge (2, 4);
g. addEdge (4, 5);
g. addEdge (1, 3);
g. addEdge (3, 5);
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