Program in C++ only You are given a graph with N nodes and M edges. Each edge has a value associated with it. There are no self-loops and multiple edges in the graph. Each edge connects two nodes. The cost of going from the first node of the edge to the second via the edge is equal to the value of the edge whereas the cost of going in the reverse direction is equal to the negative of it. Your task is to figure out if the graph is conservative or not. The cost of a path is simply the sum of the costs of each edge in the path. For each testcase, output yes if the graph is conservative otherwise no Note: Pass the below input together as one Input: 1 4 4 122 232 142 431 Output: no
Program in C++ only You are given a graph with N nodes and M edges. Each edge has a value associated with it. There are no self-loops and multiple edges in the graph. Each edge connects two nodes. The cost of going from the first node of the edge to the second via the edge is equal to the value of the edge whereas the cost of going in the reverse direction is equal to the negative of it. Your task is to figure out if the graph is conservative or not. The cost of a path is simply the sum of the costs of each edge in the path. For each testcase, output yes if the graph is conservative otherwise no Note: Pass the below input together as one Input: 1 4 4 122 232 142 431 Output: no
Computer Networking: A Top-Down Approach (7th Edition)
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Chapter1: Computer Networks And The Internet
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Program in C++

Transcribed Image Text:Program in C++ only
You are given a graph with N nodes and M edges. Each edge has a value associated with it. There are no
self-loops and multiple edges in the graph. Each edge connects two nodes. The cost of going from the
first node of the edge to the second via the edge is equal to the value of the edge whereas the cost of
going in the reverse direction is equal to the negative of it. Your task is to figure out if the graph is
conservative or not. The cost of a path is simply the sum of the costs of each edge in the path.
For each testcase, output yes if the graph is conservative otherwise no
Note: Pass the below input together as one
Input:
1
44
122
232
142
431
Output:
no
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