In the transportation problem, if the number of allocation is less than m+n-1 then it is called as non-degenerate basic feasible solution. In the transportation problem, the lowest cost entry method depend on determining the smallest cost in the cost matrix of the transportation table and allocate xij=min (ai,bj) in the cell (ij). For an assignment problem with 3 agents and 4 tasks, the assignment matrix will have 3 rows and 4 columns.
In the transportation problem, if the number of allocation is less than m+n-1 then it is called as non-degenerate basic feasible solution. In the transportation problem, the lowest cost entry method depend on determining the smallest cost in the cost matrix of the transportation table and allocate xij=min (ai,bj) in the cell (ij). For an assignment problem with 3 agents and 4 tasks, the assignment matrix will have 3 rows and 4 columns.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Transcribed Image Text:In the transportation problem, if the number of allocation is less than m+n-1 then it is
called as non-degenerate basic feasible solution.
In the transportation problem, the lowest cost entry method depend on determining
the smallest cost in the cost matrix of the transportation table and allocate xij=min
(ai,bj) in the cell (ij).
For an assignment problem with 3 agents and 4 tasks, the assignment matrix will have
3 rows and 4 columns.
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