then A-1 A = -6 0 0 0 0 8 0 0 0 0 0 -5 0 0 0 -7

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Given the matrix \( A \):

\[
A = \begin{bmatrix} 
-6 & 0 & 0 & 0 \\ 
0 & 8 & 0 & 0 \\ 
0 & 0 & -5 & 0 \\ 
0 & 0 & 0 & -7
\end{bmatrix}
\]

Then the inverse of the matrix \( A \), denoted as \( A^{-1} \), is represented by the empty structure:

\[
A^{-1} = \begin{bmatrix} 
\boxed{} & \boxed{} & \boxed{} & \boxed{} \\ 
\boxed{} & \boxed{} & \boxed{} & \boxed{} \\ 
\boxed{} & \boxed{} & \boxed{} & \boxed{} \\ 
\boxed{} & \boxed{} & \boxed{} & \boxed{}
\end{bmatrix}
\]

Explanation:
- The matrix \( A \) is a diagonal matrix, meaning all the non-diagonal elements are zeros, and the diagonal elements can be inverted by taking their reciprocal (considering inverses of the values). 
- The structure for \( A^{-1} \) is provided with empty boxes, indicating where the values should be filled in after calculating the inverse.
Transcribed Image Text:Given the matrix \( A \): \[ A = \begin{bmatrix} -6 & 0 & 0 & 0 \\ 0 & 8 & 0 & 0 \\ 0 & 0 & -5 & 0 \\ 0 & 0 & 0 & -7 \end{bmatrix} \] Then the inverse of the matrix \( A \), denoted as \( A^{-1} \), is represented by the empty structure: \[ A^{-1} = \begin{bmatrix} \boxed{} & \boxed{} & \boxed{} & \boxed{} \\ \boxed{} & \boxed{} & \boxed{} & \boxed{} \\ \boxed{} & \boxed{} & \boxed{} & \boxed{} \\ \boxed{} & \boxed{} & \boxed{} & \boxed{} \end{bmatrix} \] Explanation: - The matrix \( A \) is a diagonal matrix, meaning all the non-diagonal elements are zeros, and the diagonal elements can be inverted by taking their reciprocal (considering inverses of the values). - The structure for \( A^{-1} \) is provided with empty boxes, indicating where the values should be filled in after calculating the inverse.
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