In the molecule shown below, determine which of the highlighted C-H bonds (from a to e) is expected to have the lowest bond dissociation energy. Ho C-Ha C-Hb C-Hc C-Hd C-He

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### Bond Dissociation Energy Analysis

In the molecule shown below, determine which of the highlighted C-H bonds (from a to e) is expected to have the lowest bond dissociation energy.

![Molecule Diagram](attachment: image.jpg)

### Options:

A. \( \text{C-H}_a \)

B. \( \text{C-H}_b \)

C. \( \text{C-H}_c \)

D. \( \text{C-H}_d \)

E. \( \text{C-H}_e \)

### Analysis of the Molecule:

The given molecular structure includes several highlighted hydrogen atoms labeled \( \text{H}_a \), \( \text{H}_b \), \( \text{H}_c \), \( \text{H}_d \), and \( \text{H}_e \), which are bonded to respective carbon atoms in the cyclohexane ring, and one substituent.

### Determining Bond Dissociation Energy:

Bond dissociation energy (BDE) refers to the energy required to break a specific bond in a molecule homolytically, resulting in two radicals. Typically, factors such as bond strength, bond length, and the stability of the resulting radicals influence the dissociation energy. The actual analysis involves considering the type and environment of each C-H bond:

1. **Hyperconjugation**: Bonds adjacent to a more significant number of hydrogen atoms often show lower BDE due to hyperconjugation effects.
2. **Inductive effects**: Electronegative substituents might affect nearby C-H bonds, altering the BDE.
3. **Radical stability**: The more stable the resulting radical, the lower the bond dissociation energy.

Using these principles, one can predict that the bond with the potentially lowest dissociation energy would be the one adjacent to more stabilizing interactions (like hyperconjugation or inductive effects) or forming the most stable free radical on dissociation.

For detailed reasoning and final answer derivation, evaluating the specific electronic and structural environment of each C-H bond in the context of the molecule's geometry and substituent effects is crucial.
Transcribed Image Text:### Bond Dissociation Energy Analysis In the molecule shown below, determine which of the highlighted C-H bonds (from a to e) is expected to have the lowest bond dissociation energy. ![Molecule Diagram](attachment: image.jpg) ### Options: A. \( \text{C-H}_a \) B. \( \text{C-H}_b \) C. \( \text{C-H}_c \) D. \( \text{C-H}_d \) E. \( \text{C-H}_e \) ### Analysis of the Molecule: The given molecular structure includes several highlighted hydrogen atoms labeled \( \text{H}_a \), \( \text{H}_b \), \( \text{H}_c \), \( \text{H}_d \), and \( \text{H}_e \), which are bonded to respective carbon atoms in the cyclohexane ring, and one substituent. ### Determining Bond Dissociation Energy: Bond dissociation energy (BDE) refers to the energy required to break a specific bond in a molecule homolytically, resulting in two radicals. Typically, factors such as bond strength, bond length, and the stability of the resulting radicals influence the dissociation energy. The actual analysis involves considering the type and environment of each C-H bond: 1. **Hyperconjugation**: Bonds adjacent to a more significant number of hydrogen atoms often show lower BDE due to hyperconjugation effects. 2. **Inductive effects**: Electronegative substituents might affect nearby C-H bonds, altering the BDE. 3. **Radical stability**: The more stable the resulting radical, the lower the bond dissociation energy. Using these principles, one can predict that the bond with the potentially lowest dissociation energy would be the one adjacent to more stabilizing interactions (like hyperconjugation or inductive effects) or forming the most stable free radical on dissociation. For detailed reasoning and final answer derivation, evaluating the specific electronic and structural environment of each C-H bond in the context of the molecule's geometry and substituent effects is crucial.
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