In the Mann-whitney test, what is theadvantages and disadvantages ofcalculating the 'Ustat' with either the twomethods below prior to comparing it withUcrit?n1(n1 + 1)nin2 +R1vs:n1(n1 + 1)R12

The Mann-Whitney U test is used to compare whether there is a difference in the dependent variable…

Answered: In the Mann-whitney test, what is the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Previously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 145 pregnant mothers and finds that 3 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.1 level of significance. What are the null and alternative hypotheses? Ho: versus H,: (Type integers or decimals. Do not round.)
Suppose you were trying to determine if there was a difference in the means of 4 different groups, and instead of using an ANOVA test, you decided to carry out 6 separate 2-sample t-tests to compare every possible combination of groups and you set the Type I error rate as a = 0.05on all of those tests. Use this information and calculate the familywise Type I error rate for this scenario. Make sure to round your answer to 3 decimal places. For example, if you thought the answer was 0.12345 then you would type in 0.123.
An experiment to investigate the effect of 4 diets on milk yield was conducted using a standard latin square design as follows. There were 4 cows available for the experiment. For each of the 4 lactation periods the cows received a different diet. Below is an incomplete table of the ANOVA of the milk yields. (a) Complete the ANOVA table below. ANOVA Table Source df SS MS F Diet 40.6875 Cow 54.6875 Lactation Period 147.1875 Error Total 247.4375 (14) (b) Are the the diet effects on milk yield significantly different from zero? Use the 0.05 level of significance. (6)
Suppose it was found that in a random sample of 200 individuals who were underweight (defined as having a BMI of under 18.5), 8 of them were hospitalized with COVID-19. Of a corresponding group of 400 individuals who were classified as severely obese (defined as having a BMI of at least 45.0), 32 were hospitalized with COVID-19. (a) What are the two sample proportions (to 4 decimal places)? (b) What is the difference between the two sample proportions (to 4 decimal places)? (c) If you were testing whether the probability of being hospitalized with COVID-19 differed between the population of underweight individuals and the population of severely obese individuals, what would be your null hypothesis, either in words or in mathematical terms?
A marketing researcher introduces two toys to each of 50 girls and 50 boys. Of these: 20 girls choose toy 1 and 30 girls choose toy 2; 30 boys choose toy 1 and 20 choose toy 2. Set up a 2 x 2 contingency table and run a chi-square test. Look at the p-value. So - is there a significant sex difference in toy preference? Use this web-based calculator: Chi Square Calculator 2x2 (socscistatistics.com) Call row 1 girls and row 2 boys (arbitrary which row you call what), and call column 1 toy 1 and column 2 toy 2. Then enter the frequencies in each of the four cells. Then click on calculate.
The degrees of freedom is critical to computing the p-value for the chi-square goodness of fit. We will discuss the p-value in the next lab. The degrees of freedom for the Chi-Square goodness of fit is equal to (the number of non-zero rows in the table) - 1. The number of non-zero rows is the number of expected values that are non-zero. For example: Phenotype ... Expected ... Disease ... 234 ... Wild-type ... 6743 ... has two rows where the Expected value is non-zero. So the degrees of freedom is 2-1 = 1. Another example: Phenotype ... Expected ... Disease ... 2374 ... Wild-type ... 0 ... has one row where the Expected value is non-zero. So the degrees of freedom is 1-1 = 0. With 0 degrees of freedom, the chi-square test cannot be calculated. A third example (sex-linked): Phenotype ... Expected ... Disease-Male ... 2374 ... Disease-Female ... 9456 Wild-type-Male ... 1001 ... Wild-type-Female ... 235 ... has four rows where the Expected values are…
14% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 325 people from the inner city surveyed, 62 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? Round numerical answers to 3 decimal places For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different from 14% at αα = 0.05, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is different…
I am needing help with how to answer this in R. 1. A [national survey](http://www.pewinternet.org/2012/11/01/how-teens-do-research-in-the-digital-world/) in 2012 showed that 75% of middle and high school teachers believe their students use Wikipedia for typical research statements. Let X equal the number of teachers in a random sample of size n = 40 who believe their students use Wikipedia. i) How is X distributed? ii) Use `plotDist()` to draw the probability distribution of X. iii) Compute the probability that X is equal to 30.
Only 15% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 363 randomly selected registered voters surveyed, 58 of them will vote in the upcoming election. What can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = (please enter a decimal) H1:H1: ? μ p Select an answer = < ≠ > (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly higher than 15% at αα = 0.01, so there…
a) What is Fcrit for a one way ANOVA with 5 treatments and 6 replicates per treatment at α=0.05? b)What is Fcrit for a one way ANOVA with 3 treatments and 5 replicates per treatment at α=0.01?
Could also you please show how to find Critial Values, Test Statisitc T, and the P value using a Calculator (TI 84) and whether it reject or fail to reject based on the evidence.
A random sample of 200 middle school students was collected and the students were asked the question, "If you could have only one type of pet, what would it be?” The responses, separated by grade, are shown in the table. A teacher wants to perform a chi-square test of independence/association on the data. Are the conditions for such a test met? A. Yes, the sample size of 200 is large B. Yes, all the expected cell counts are 5 or higher. C. Yes, all the observed cell counts are 5 or higher. D. No, not all the observed counts are above 5. E. No, some of the expected cell counts are below 5.

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In the Mann-whitney test, what is the advantages and disadvantages of calculating the 'Ustat' with either the two methods below prior to comparing it with Ucrit? n1(n1 + 1) nin2 + R1 vs: n1(n1 + 1) R1 -