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In the following diagram, use Kirchhoff's rules to solve エ」 Is current passing through6 ohm resistor, Iz = ? 62 12V エレ 42 I}

In the following diagram, use Kirchhoff's rules to solve エ」 Is current passing through6 ohm resistor, Iz = ? 62 12V エレ 42 I}

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Text:** In the following diagram, use Kirchhoff's rules to solve the current passing through 6 ohm resistor, \(I_2 = ?\) **Diagram Explanation:** The diagram is a circuit schematic containing the following components: 1. **Resistors:** - An 8 ohm resistor in the top left segment. - A 6 ohm resistor in the middle segment. - A 3 ohm resistor in the top right segment. - A 4 ohm resistor in the bottom segment. 2. **Voltage Sources:** - An 8V voltage source on the left side of the circuit. - A 12V voltage source on the right side, with the positive terminal at the top. 3. **Current Loops:** - A left loop indicated with the current \(I_1\). - A middle loop indicated with the current \(I_2\) passing through the 6 ohm resistor. - A right loop indicated with the current \(I_3\). 4. **Connections:** - The 8 ohm resistor and the 8V voltage source are in series with current \(I_1\). - The 6 ohm resistor has current \(I_2\) going through it, with the loop including the 8V and 12V sources. - The 3 ohm resistor and the 12V voltage source are in series with current \(I_3\). - The 4 ohm resistor is connected in the bottom segment of the loop with current \(I_3\). The goal is to determine the current \(I_2\) using Kirchhoff's rules, particularly Kirchhoff’s loop rule, which states that the sum of the electromotive forces (e.m.f.) and the potential differences (voltages) around any closed loop is zero.
Transcribed Image Text:**Text:** In the following diagram, use Kirchhoff's rules to solve the current passing through 6 ohm resistor, \(I_2 = ?\) **Diagram Explanation:** The diagram is a circuit schematic containing the following components: 1. **Resistors:** - An 8 ohm resistor in the top left segment. - A 6 ohm resistor in the middle segment. - A 3 ohm resistor in the top right segment. - A 4 ohm resistor in the bottom segment. 2. **Voltage Sources:** - An 8V voltage source on the left side of the circuit. - A 12V voltage source on the right side, with the positive terminal at the top. 3. **Current Loops:** - A left loop indicated with the current \(I_1\). - A middle loop indicated with the current \(I_2\) passing through the 6 ohm resistor. - A right loop indicated with the current \(I_3\). 4. **Connections:** - The 8 ohm resistor and the 8V voltage source are in series with current \(I_1\). - The 6 ohm resistor has current \(I_2\) going through it, with the loop including the 8V and 12V sources. - The 3 ohm resistor and the 12V voltage source are in series with current \(I_3\). - The 4 ohm resistor is connected in the bottom segment of the loop with current \(I_3\). The goal is to determine the current \(I_2\) using Kirchhoff's rules, particularly Kirchhoff’s loop rule, which states that the sum of the electromotive forces (e.m.f.) and the potential differences (voltages) around any closed loop is zero.
Expert Solution
Step 1

Use Kirchhoff’s junction rule in the given circuit as follows.

I2+I3=I1

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