In the figure, two speakers separated by distance d, = 2.00 m are in phase. You are standing 4.00 m directly in front of one speaker. Each speaker has an output power of 1.30 W. Because the speakers are at different distances, there will be frequencies at which thesound from the speakers interferes destructively. But because the speakers are at different distances, the sound intensities will not be the same, so the destructive interference will not be complete. We want to find the sound level when there is destructive interference.Use 343 m/s for the speed of sound in air.SpeakersListener(a) What is the lowest frequency that gives minimum signal (destructive interference) at your ear?Hz(b) What is the second lowest frequency that gives minimum signal?Hz(c) What is the intensity from the near speaker? (note: keep 6 significant figures or rounding may screw up your answer to part f)W/m2(d) This part intentionally left blank(e) What is the intensity from the far speaker? (note: keep 6 sigfigs)W/m2(f) What is the combined intensity during destructive interference? Because the sources are coherent, amplitudes add (or subtract) but intensities do not.W/m2

Solution: Firstly, Let us find the distance between the second speaker to the listener:…

Answered: In the figure, two speakers separated…

Similar questions

Sound with a 29 cm wavelength travels rightward from a source and through a tube that consists of a straight portion and a half-circle. Part of the soundwave travels through the circle and rejoins the the rest of the wave which goes directly through the straight portion. This rejoining results in interference. What is the smallest radius r (in cm) that results in an intensity minimum at the detector. The maximum destructive interference will occur when the difference in the distance travelled by the two waves is 1/2 of a wavelength. To solve this problem express the difference in the distance travelled by the two waves as a function of r and set this amount equal to 1/2 of a wavelength.
A 1,720-Hz tone is played on a stereo in an open field. A person stands at a point that is 4 m from one of the speakers and 4.4 m from the other. What must the minimum wavelength be for the person to hear the tone? (Hint: because of interference, two waves add constructively or destructively. If the sound is heard the interference must be constructive. For interference to be constructive, the difference in distance must be a multiple of the wavelength. That is, the difference in distances from the speakers must be 1 wavelength, two wavelengths, three wavelengths, etc.)
Two speakers recieve the same 256 Hz signal from an amplifier. When one speaker is placed directly behind the other, what is the smallest distance between them that produces destructive interference at any point in front of them?(speed of sound=342m/s)
Two identical loudspeakers are placed on a wall 3.00 m apart. A listener stands 5.00 m from the wall directly in front of one of the speakers. A single oscillator is driving the speakers at a frequency of 300 Hz. (a) What is the phase difference in radians between the waves from the speakers when they reach the observer? (Your answer should be between 0 and 2.7.) rad (b) What is the frequency closest to 300 Hz to which the oscillator may be adjusted such that the observer hears minimal sound? Hz
Speaker 1 is at x = 0 and speaker 2 is to the right and facing it at x = 8 m. The speakers are to the same amplifier, which plays a tone at 327 Hz. Find the x-coordinate in meters of the first point of constructive interference that is right of center, if the temperature in the room is 18°C. connected continuous Take the speed of sound to be T v = (331 m/s) √ 273 K X = 3
A 1,720-Hz tone is played on a stereo in an open field. A person stands at a point that is 4 m from one of the speakers and 4.4 m from the other. What must the minimum wavelength be for the person to hear the tone? (Hint: because of interference, two waves add constructively or destructively. If the sound is heard the interference must be constructive. For interference to be constructive, the difference in distance must be a multiple of the wavelength. That is, the difference in distances from the speakers must be 1 wavelength, two wavelengths, three wavelengths, etc.)