In the figure is shown a battery having an emf of 12 Volts and an internal resistance of 0.40 Ohm. A resistor R, of 2.6 Ohms is connected across terminals ab. Determine (a) resistance of R its which, when connected across terminals ab in E = 12 V R,= 2.62 parallel with R, will make the power delivered by the battery a maximum; (b) current in R, and R; (c) terminal voltage of battery; (d) power in R, and in R; (e) power lost in battery r = 0.40 Q- Hint: To maximize power in R, use differentiation
In the figure is shown a battery having an emf of 12 Volts and an internal resistance of 0.40 Ohm. A resistor R, of 2.6 Ohms is connected across terminals ab. Determine (a) resistance of R its which, when connected across terminals ab in E = 12 V R,= 2.62 parallel with R, will make the power delivered by the battery a maximum; (b) current in R, and R; (c) terminal voltage of battery; (d) power in R, and in R; (e) power lost in battery r = 0.40 Q- Hint: To maximize power in R, use differentiation
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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In the figure is shown a battery having an emf of 12 Volts and an internal resistance of 0.40 Ohm. A resistor R1 of 2.6 Ohms is connected across its terminals ab. Determine (a) resistance of R which, when connected across terminals ab in parallel with R1 will make the power delivered by the battery a maximum; (b) current in R1 and R; (c) terminal voltage of battery; (d) power in R1 and in R; (e) power lost in battery Hint: To maximize power in R, use differentiation.
Transcribed Image Text:In the figure is shown a battery having an emf of 12 Volts and an internal resistance of 0.40 Ohm.
A resistor R, of 2.6 Ohms is connected across
terminals ab. Determine (a) resistance of R
which, when connected across terminals ab in
parallel with R will make the power
its
E = 12 V +
R,= 2.62
r = 0.40 Q-
delivered by the battery a maximum; (b)
current in R, and R; (c) terminal voltage of
battery; (d) power in R, and in R; (e) power lost in battery
Hint: To maximize power in R, use differentiation
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